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双二甲酮衍生物的包装考量

Packing considerations of bis-dimedone derivatives.

作者信息

Bolte M, Degen A, Rühl S

机构信息

Institut für Organische Chemie, J. W. Goethe-Universität Frankfurt, Marie-Curie-Strasse 11, 60439 Frankfurt/Main, Germany.

出版信息

Acta Crystallogr C. 2001 Apr;57(Pt 4):446-51. doi: 10.1107/s0108270101001792.

Abstract

We have determined the crystal structures of 2,2'-(4-fluorophenyl)methylenebis(3-hydroxy-5,5-dimethyl-2-cyclohexen-1-one), C(23)H(27)FO(4), (I), 2,2'-(4-chlorophenyl)methylenebis(3-hydroxy-5,5-dimethyl-2-cyclohexen-1-one), C(23)H(27)ClO(4), (II), 2,2'-(4-hydroxyphenyl)methylenebis(3-hydroxy-5,5-dimethyl-2-cyclohexen-1-one), C(23)H(28)O(5), (III), 2,2'-(4-methylphenyl)methylenebis(3-hydroxy-5,5-dimethyl-2-cyclohexen-1-one), C(24)H(30)O(4), (IV), 2,2'-(4-methoxyphenyl)methylenebis(3-hydroxy-5,5-dimethyl-2-cyclohexen-1-one), C(24)H(30)O(5), (V), and 2,2'-(4-N,N'-dimethylaminophenyl)methylenebis(3-hydroxy-5,5-dimethyl-2-cyclohexen-1-one), C(25)H(33)NO(4), (VI). Structures (III) to (VI) of these bis-dimedone derivatives show nearly the same packing pattern irrespective of the different substituent in the para position of the aromatic ring. However, (II) does not fit into this scheme, although the Cl atom is a substituent not too different from the others. The different packing of the fluoro compound, (I), can be explained by the fact that it crystallizes with two molecules in the asymmetric unit, which show a different conformation of the dimedone ring. On the other hand, (I) shows a similar packing pattern to bis(2-hydroxy-4,4-dimethyl-6-oxo-1-cyclohexenyl)phenylmethane, a compound containing an aromatic ring without any substituent and with Z' = 2.

摘要

我们已测定了2,2'-(4-氟苯基)亚甲基双(3-羟基-5,5-二甲基-2-环己烯-1-酮),C(23)H(27)FO(4),(I)、2,2'-(4-氯苯基)亚甲基双(3-羟基-5,5-二甲基-2-环己烯-1-酮),C(23)H(27)ClO(4),(II)、2,2'-(4-羟基苯基)亚甲基双(3-羟基-5,5-二甲基-2-环己烯-1-酮),C(23)H(28)O(5),(III)、2,2'-(4-甲基苯基)亚甲基双(3-羟基-5,5-二甲基-2-环己烯-1-酮),C(24)H(30)O(4),(IV)、2,2'-(4-甲氧基苯基)亚甲基双(3-羟基-5,5-二甲基-2-环己烯-1-酮),C(24)H(30)O(5),(V)以及2,2'-(4-N,N'-二甲基氨基苯基)亚甲基双(3-羟基-5,5-二甲基-2-环己烯-1-酮),C(25)H(33)NO(4),(VI)的晶体结构。这些双二甲基酮衍生物的(III)至(VI)结构显示出几乎相同的堆积模式,而与芳环对位上不同的取代基无关。然而,(II)并不符合此模式,尽管氯原子是与其他取代基差异不算太大的一个取代基。氟代化合物(I)的不同堆积情况可通过以下事实来解释:它在不对称单元中以两个分子结晶,这两个分子显示出二甲基酮环的不同构象。另一方面,(I)显示出与双(2-羟基-4,4-二甲基-6-氧代-1-环己烯基)苯基甲烷相似的堆积模式,双(2-羟基-4,4-二甲基-6-氧代-1-环己烯基)苯基甲烷是一种不含任何取代基且Z' = 2的含芳环化合物。

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