Simón Ernesto, Barceló Anna, Ariño Joaquín
Departament de Bioquímica i Biologia Molecular, Universitat Autònoma de Barcelona, Bellaterra 08193, Barcelona, Spain.
FEBS Lett. 2003 Jun 19;545(2-3):239-45. doi: 10.1016/s0014-5793(03)00557-x.
The yeast Nha1 Na(+),K(+)/H(+) antiporter may play an important role in regulation of cell cycle, as high-copy expression of the NHA1 gene is able to rescue the blockage at the G(1)/S transition of cells lacking Sit4 protein phosphatase and Hal3 activities. Interestingly, this function was independent of the role of the antiporter in improving tolerance to sodium cations, it required the integrity of a relatively large region (from residues 800 to 948) of its carboxy-terminal moiety, and was not performed by the fission yeast homolog antiporter Sod2, which lacks a carboxy-terminal tail. Here we show that a hybrid protein composed of the Sod2 antiporter fused to the carboxy-terminal half of Nha1 strongly increased sodium tolerance, but did not allow growth at high potassium nor did rescue growth of the sit4 hal3 conditional mutant strain. Deletion of Nha1 residues from 800 to 849, 900 to 925 or 926 to 954 abolished the function of Nha1 in cell cycle without affecting sodium tolerance. A screening for loss-of-function mutations at the 775-980 carboxy-terminal tail of Nha1 has revealed a number of residues required for function in cell cycle, most of them clustering in two regions, from residues 869 to 876 (cluster A) and 918 to 927 (cluster B). The later is rather conserved in other related antiporters, while the former is not.
酵母Nha1钠钾/氢反向转运蛋白可能在细胞周期调控中发挥重要作用,因为NHA1基因的高拷贝表达能够挽救缺乏Sit4蛋白磷酸酶和Hal3活性的细胞在G1/S期转换时的阻滞。有趣的是,该功能独立于反向转运蛋白在提高对钠离子耐受性方面的作用,它需要其羧基末端部分相对较大区域(从第800位到948位残基)的完整性,并且不是由缺乏羧基末端尾巴的裂殖酵母同源反向转运蛋白Sod2执行的。在这里我们表明,由Sod2反向转运蛋白与Nha1的羧基末端一半融合而成的杂合蛋白强烈提高了钠耐受性,但不允许在高钾条件下生长,也不能挽救sit4 hal3条件突变菌株的生长。删除Nha1从第800位到849位、900位到925位或926位到954位的残基消除了Nha1在细胞周期中的功能,而不影响钠耐受性。对Nha1羧基末端尾巴775-980位的功能丧失突变进行筛选,发现了许多在细胞周期功能中所需的残基,其中大多数聚集在两个区域,从第869位到876位残基(簇A)和918位到927位残基(簇B)。后者在其他相关反向转运蛋白中相当保守,而前者则不然。