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重复基因的不对称序列分歧。

Asymmetric sequence divergence of duplicate genes.

作者信息

Conant Gavin C, Wagner Andreas

机构信息

Department of Biology, The University of New Mexico, Albuquerque, New Mexico 87131, USA.

出版信息

Genome Res. 2003 Sep;13(9):2052-8. doi: 10.1101/gr.1252603.

Abstract

Much like humans, gene duplicates may be created equal, but they do not stay that way for long. For four completely sequenced genomes we show that 20%-30% of duplicate gene pairs show asymmetric evolution in the amino acid sequence of their protein products. That is, one of the duplicates evolves much faster than the other. The greater this asymmetry, the greater the ratio Ka/Ks of amino acid substitutions (Ka) to silent substitutions (Ks) in a gene pair. This indicates that most asymmetric divergence may be caused by relaxed selective constraints on one of the duplicates. However, we also find some candidate duplicates where positive (directional) selection of beneficial mutations (Ka/Ks > 1) may play a role in asymmetric divergence. Our analysis rests on a codon-based model of molecular evolution that allows a test for asymmetric divergence in Ka. The method is also more sensitive in detecting positive selection (Ka/Ks > 1) than models relying only on pairwise gene comparisons.

摘要

与人类非常相似,基因复制体可能最初是相同的,但它们不会长期保持这种状态。对于四个已完全测序的基因组,我们发现20% - 30%的复制基因对在其蛋白质产物的氨基酸序列中呈现出不对称进化。也就是说,其中一个复制体的进化速度比另一个快得多。这种不对称性越大,基因对中氨基酸替换(Ka)与沉默替换(Ks)的比率Ka/Ks就越大。这表明大多数不对称分歧可能是由于对其中一个复制体的选择性限制放松所致。然而,我们也发现了一些候选复制体,其中有益突变的正向(定向)选择(Ka/Ks > 1)可能在不对称分歧中起作用。我们的分析基于一种基于密码子的分子进化模型,该模型允许对Ka中的不对称分歧进行测试。与仅依赖成对基因比较的模型相比,该方法在检测正向选择(Ka/Ks > 1)方面也更敏感。

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