BACHOFER C S, POTTINGER M A
J Gen Physiol. 1954 May 20;37(5):663-75. doi: 10.1085/jgp.37.5.663.
Various levels of protection against x-irradiation damage in bacteriophage T1 may be obtained by the addition of inorganic salts to the aqueous virus suspensions during irradiation. The highest survival values are obtained with the nitrite salts, and their protective power is attributed primarily to their function as reducing agents. The nitrate ion shows greater protection than the corresponding sulfate or chloride ions. This may be due in part to the lower energy level of the nitrate ion, by reason of resonance. Since greater expenditure of incident energy is required to raise the ion from the ground state, the energy thus dissipated may be ineffective in the inactivation of virus particles. The ammonium salts exhibit protection of a different order of magnitude from that of the metallic salts. It is postulated that NH(4) (+) protects in a threefold way: (a) dehydration, (b) reduction, in which the ammonia is oxidized to nitrite and the nitrite to nitrate, and (c) stabilization of the virus protein. Metallic salts likewise protect, but a point of maximum protection is reached in lower concentrations than in the case of the ammonium salts. After this maximum protection is reached, there is a rapid decline in survival with increased concentration. This prevents protection of the order of magnitude that can be obtained with the ammonium salts. It is postulated that a specific cationic interaction with the phage may be responsible for the decreased protection. Bacteriophage is protected during x-irradiation by an alkaline pH, in the case of NH(4)OH. This protection could not be produced with NaOH, presumably because of the greater hydrolysis of the protein components of the virus particle in solutions of NaOH, whereas NH(4)OH stabilizes the protein.
在噬菌体T1受到X射线照射时,通过在照射期间向水性病毒悬浮液中添加无机盐,可以获得不同程度的抗X射线辐射损伤保护。亚硝酸盐能使噬菌体获得最高的存活率,其保护能力主要归因于它们作为还原剂的功能。硝酸根离子比相应的硫酸根或氯离子表现出更强的保护作用。这可能部分归因于硝酸根离子由于共振而具有较低的能级。由于将离子从基态提升需要消耗更多的入射能量,因此这样耗散的能量可能对病毒颗粒的失活无效。铵盐表现出与金属盐不同数量级的保护作用。据推测,NH₄⁺以三种方式起到保护作用:(a)脱水,(b)还原,其中氨被氧化为亚硝酸盐,亚硝酸盐再被氧化为硝酸盐,以及(c)稳定病毒蛋白。金属盐同样具有保护作用,但达到最大保护作用时的浓度低于铵盐的情况。在达到这种最大保护作用后,随着浓度增加存活率会迅速下降。这使得无法获得与铵盐相同数量级的保护。据推测,与噬菌体的特定阳离子相互作用可能是保护作用降低的原因。在X射线照射期间,噬菌体在碱性pH条件下受到保护,如在NH₄OH的情况下。而NaOH无法产生这种保护作用,大概是因为在NaOH溶液中病毒颗粒的蛋白质成分水解程度更大,而NH₄OH能使蛋白质稳定。