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基于66种食物粪便膨胀指数得出的膳食纤维适宜摄入量值。

Adequate intake values for dietary fibre based on faecal bulking indexes of 66 foods.

作者信息

Monro J A

机构信息

New Zealand Institute for Crop & Food Research, Palmerston North, New Zealand.

出版信息

Eur J Clin Nutr. 2004 Jan;58(1):32-9. doi: 10.1038/sj.ejcn.1601741.

DOI:10.1038/sj.ejcn.1601741
PMID:14679364
Abstract

OBJECTIVE

To determine an adequate daily intake value for dietary fibre (AIdf) based on faecal bulking indexes (FBIs) for 66 foods of known total dietary fibre (TDF) content.

DESIGN

FBIs of 66 foods were measured and expressed as wheat bran equivalents (WBEfb) per 100 g of food. A daily WBEfb requirement for humans was calculated from faecal bulk generated per gram of wheat bran TDF in humans, using a critical faecal mass of 200 g/day for protection against large bowel disease. TDF content was regressed against WBEfb content for all 66 foods assayed, and an AIdf value obtained by substituting the calculated human WBEfb requirement into the regression equation.

METHOD

FBI was measured using a validated rat assay, with eight large (400+/-50 g) rats per group, preadapted to dietary fibre, and fed adequate restricted diets containing test foods at inclusion rates consistent with human intakes. The critical faecal mass was based on epidemiological studies, and the faecal bulk generated per gram of wheat bran TDF was the mean of 27 published values.

RESULTS

WBEfb requirements for humans were calculated to be 90 g/day, corresponding to a faecal output of 200 g/day. The regression equation relating WBEfb measured in the FBI assay to TDF in all 66 foods was TDF=0.491WBEfb + 3.19, R2=0.81 Substituting the human WBEfb requirement of 90 g into the regression equation gave an AIdf value of 40.9 g TDF/day.

CONCLUSION

The AIdf value of 40.9 g TDF/day based on faecal bulking supports the AIdf of 38 g TDF/day recently set by the Institute of Medicine (USA), for young men, based on protection against heart disease. The AIdf value is obtained from the relation between the effects of foods and their content of mixed function, plant cell wall dietary fibres within the food matrices, and should not be used to guide intakes of extrinsic functional polysaccharides.

摘要

目的

根据已知总膳食纤维(TDF)含量的66种食物的粪便膨松指数(FBI),确定膳食纤维的适宜每日摄入量值(AIdf)。

设计

测量66种食物的FBI,并表示为每100克食物的麦麸当量(WBEfb)。根据人类每克麦麸TDF产生的粪便量,计算出人类每日WBEfb需求量,使用200克/天的临界粪便量来预防大肠疾病。对所有66种被测食物的TDF含量与WBEfb含量进行回归分析,并通过将计算出的人类WBEfb需求量代入回归方程获得AIdf值。

方法

使用经过验证的大鼠试验测量FBI,每组8只大型(400±50克)大鼠,预先适应膳食纤维,并喂食含测试食物的充足受限饮食,其添加率与人类摄入量一致。临界粪便量基于流行病学研究,每克麦麸TDF产生的粪便量是27个已发表值的平均值。

结果

计算出人类对WBEfb的需求量为90克/天,对应粪便产量为200克/天。在FBI试验中测得的WBEfb与所有66种食物中的TDF之间的回归方程为TDF = 0.491WBEfb + 3.19,R2 = 0.81。将人类WBEfb需求量90克代入回归方程,得出AIdf值为40.9克TDF/天。

结论

基于粪便膨松得出的40.9克TDF/天的AIdf值,支持美国医学研究所最近为预防心脏病为年轻男性设定的38克TDF/天的AIdf值。AIdf值是从食物的作用与其在食物基质中混合功能的植物细胞壁膳食纤维含量之间的关系得出的,不应被用于指导外源性功能性多糖的摄入量。

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