Tobías Gerard, Beltrán-Porter Daniel, Lebedev Oleg I, Van Tendeloo Gustaaf, Rodríguez-Carvajal Juan, Fuertes Amparo
Institut de Ciència de Materials de Barcelona (CSIC), Campus UAB, 08193 Bellaterra, Spain.
Inorg Chem. 2004 Dec 13;43(25):8010-7. doi: 10.1021/ic049236k.
The crystal structure of the n = 1 member of the Ruddlesden-Popper family (SrO)(SrNbO(2)N)(n) was refined by the Rietveld method using neutron powder diffraction data. This complex crystallizes in the I4/mmm space group with cell parameters a = 4.0506(2) and c = 12.5936(9) angstroms. The refined composition was Sr(2)NbO(3.28)N(0.72), which corresponds to a formal oxidation state for Nb of +4.72, meaning 72% Nb(V) and 28% Nb(IV). The nitrogen atoms order in the equatorial sites of the niobium octahedra according to Pauling's second crystal rule as the more charged anion occupies the site showing the larger bond strength sums. Pauling's second crystal rule is shown to be able to predict the distribution of anions in the available crystallographic sites in other mixed anion systems such as oxyhalides with K(2)NiF(4) structures and other oxynitrides. The defect structure of the n = 1 and n = 2 members of the same family was investigated by high-resolution electron microscopy. Recurrent intergrowth along the c axis with other Ruddlesden-Popper members (n = 3, 4, and perovskite) is observed, resulting in streaking along this direction in the corresponding electron diffraction patterns.
利用中子粉末衍射数据,通过Rietveld方法对Ruddlesden-Popper家族n = 1成员(SrO)(SrNbO₂N)ₙ的晶体结构进行了精修。该化合物结晶于I4/mmm空间群,晶胞参数a = 4.0506(2) Å,c = 12.5936(9) Å。精修后的组成为Sr₂NbO₃.₂₈N₀.₇₂,对应Nb的形式氧化态为 +4.72,即72%的Nb(V)和28%的Nb(IV)。根据鲍林第二晶体规则,氮原子在铌八面体的赤道位置有序排列,因为电荷更多的阴离子占据键强总和更大的位置。结果表明,鲍林第二晶体规则能够预测其他混合阴离子体系(如具有K₂NiF₄结构的卤氧化物和其他氮氧化物)中可用晶体学位置上阴离子的分布。通过高分辨率电子显微镜研究了同一家族n = 1和n = 2成员的缺陷结构。观察到沿c轴与其他Ruddlesden-Popper成员(n = 3、4和钙钛矿)反复共生,导致在相应电子衍射图中沿该方向出现条纹。