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通过融合孔的释放事件的幅度分布。

The amplitude distribution of release events through a fusion pore.

作者信息

Jones Stephen W, Friel David D

机构信息

Department of Physiology and Biophysics, Case Western University, Cleveland, OH 44106, USA.

出版信息

Biophys J. 2006 Mar 1;90(5):L39-41. doi: 10.1529/biophysj.105.078881. Epub 2006 Jan 13.

Abstract

Neurotransmitters, hormones, or dyes may be released from vesicles via a fusion pore, rather than by full fusion of the vesicle with the plasma membrane. If the lifetime of the fusion pore is comparable to the time required for the substance to exit the vesicle, only a fraction of the total vesicle content may be released during a single pore opening. Assuming 1), fusion pore lifetimes are exponentially distributed (tauP), as expected for simple single channel openings, and 2), vesicle contents are lost through the fusion pore with an exponential time course (tauD), we derive an analytical expression for the probability density function of the fraction of vesicle content released (F): dP/dF=A (1-F)(A-1), where A=tauD/tauP. If A>1, the maximum of the distribution is at F=0; if A<1, the maximum is at F=1; if A=1, the distribution is perfectly flat. Thus, the distribution never has a peak in the middle (0<F<1). This should be considered when interpreting the distribution of miniature synaptic currents, or the fraction of FM dye molecules lost during a single fusion pore opening event.

摘要

神经递质、激素或染料可能通过融合孔从囊泡中释放,而不是通过囊泡与质膜的完全融合。如果融合孔的寿命与物质从囊泡中排出所需的时间相当,那么在单个孔开放期间,可能只有一部分囊泡总内容物被释放。假设:1)融合孔寿命呈指数分布(τP),这与简单单通道开放的预期情况相同;2)囊泡内容物通过融合孔以指数时间进程丢失(τD),我们推导出了囊泡内容物释放分数(F)的概率密度函数的解析表达式:dP/dF = A(1 - F)(A - 1),其中A = τD/τP。如果A>1,分布的最大值在F = 0处;如果A<1,最大值在F = 1处;如果A = 1,分布是完全平坦的。因此,分布在中间(0<F<1)处永远不会有峰值。在解释微小突触电流的分布或单个融合孔开放事件中丢失的FM染料分子分数时,应考虑到这一点。

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