Liochev S I, Fridovich I
Department of Biochemistry, Duke University Medical Center, Durham, North Carolina 27710.
Arch Biochem Biophys. 1991 Dec;291(2):379-82. doi: 10.1016/0003-9861(91)90149-d.
V(IV) decomposed H2O2, with evolution of O2, in a free radical chain process involving O2- and HO(.). When V(IV) was limiting, the presence of V(V) augmented O2 evolution because it allowed production of additional V(IV) from the reduction of V(V) by O2-. Gradual addition of V(IV) increased the yield of O2 evolved, per V(IV) added, to greater than 1--a clear indication of a free radical chain reaction. Reductants such as ethanol, Hepes, and NADH imposed a phase of O2 consumption because of HO.-initiated oxidation reactions. The radical produced from the reaction of HO. with ethanol was unable to directly oxidize NADH, whereas that produced from Hepes was able to do so. Ethanol consequently inhibited the oxidation of NADH by anaerobic V(IV) + H2O2, whereas Hepes did not. These results, and others reported herein, are explained on the basis of a coherent set of reactions. Data already in the literature are also clarified on the basis of these reactions.
四价钒(V(IV))在涉及超氧阴离子(O2-)和羟基自由基(HO(.))的自由基链式反应中分解过氧化氢(H2O2)并释放氧气(O2)。当四价钒有限时,五价钒(V(V))的存在会增加氧气的释放,因为超氧阴离子可将五价钒还原为四价钒,从而产生更多的四价钒。逐步添加四价钒会使每添加的四价钒所释放的氧气产量增加至大于1,这清楚地表明了自由基链式反应。诸如乙醇、羟乙基哌嗪乙磺酸(Hepes)和烟酰胺腺嘌呤二核苷酸(NADH)等还原剂会导致氧气消耗阶段,这是由于羟基自由基引发的氧化反应。羟基自由基与乙醇反应产生的自由基无法直接氧化NADH,而与Hepes反应产生的自由基则能够氧化NADH。因此,乙醇会抑制厌氧条件下四价钒 + 过氧化氢对NADH的氧化,而Hepes则不会。本文报道的这些结果以及其他结果均基于一组连贯的反应得到了解释。文献中已有的数据也基于这些反应得到了澄清。