Zhou Dong, Carlson Kathryn E, Katzenellenbogen John A, Welch Michael J
Mallinckrodt Institute of Radiology, Washington University School of Medicine, St. Louis, Missouri 63110, USA.
J Med Chem. 2006 Jul 27;49(15):4737-44. doi: 10.1021/jm060348q.
Progesterone receptors (PRs) are present in many breast tumors, and their levels are increased by certain endocrine therapies. We describe the synthesis and PR binding affinities of a series of bromine- and iodine-substituted 16alpha,17alpha-dioxolane progestins, some of which, when appropriately radiolabeled, are potential agents for diagnostic imaging of PR-positive breast tumors using positron emission tomography (PET) and for radiotherapy. These compounds were synthesized from halogenated furanyl, phenyl, and thiophenyl aldehydes and a progestin 16alpha,17alpha,21-triol (5) in the presence of HClO4 or Sc(OTf)3 in high yields under optimized conditions. A new reagent, perfluoro-1-butanesulfonyl fluoride (PBSF), was used to convert the C-21 OH to F in high yields. The relative binding affinities (RBAs) of the most promising compounds for the PR (RBA of R5020 = 100) were 16alpha,17alpha-[(R)-1'-alpha-(5-bromofurylmethylidene)dioxyl]-21-hydroxy-19-norpregn-4-ene-3,20-dione (endo-6; RBA = 65 and moderate lipophilicity), 21-fluoro-16alpha,17alpha-[(R)-1'-alpha-(5-iodofurylmethylidene)dioxyl]-19-norpregn-4-ene-3,20-dione (endo-14; RBA = 40) and 21-fluoro-16alpha,17alpha-[(S)-1'-beta-(4-iodophenylmethylidene)dioxyl]-19-norpregn-4-ene-3,20-dione (exo-16; RBA = 34).
孕激素受体(PRs)存在于许多乳腺肿瘤中,其水平会因某些内分泌疗法而升高。我们描述了一系列溴代和碘代的16α,17α-二氧戊环类孕激素的合成及其与PR的结合亲和力,其中一些经适当放射性标记后,有可能成为使用正电子发射断层扫描(PET)对PR阳性乳腺肿瘤进行诊断成像以及用于放射治疗的药物。这些化合物是在高氯酸或三氟甲磺酸钪存在下,由卤代呋喃基、苯基和噻吩基醛与孕激素16α,17α,21-三醇(5)在优化条件下高产率合成的。一种新试剂全氟-1-丁烷磺酰氟(PBSF)被用于将C-21位的羟基高产率地转化为氟。最有前景的化合物对PR的相对结合亲和力(RBA,R5020的RBA = 100)分别为16α,17α-[(R)-1'-α-(5-溴代呋喃基亚甲基)二氧戊环]-21-羟基-19-去甲孕-4-烯-3,20-二酮(内型-6;RBA = 65,亲脂性适中)、21-氟-16α,17α-[(R)-1'-α-(5-碘代呋喃基亚甲基)二氧戊环]-19-去甲孕-4-烯-3,20-二酮(内型-14;RBA = 40)和21-氟-16α,17α-[(S)-1'-β-(4-碘代苯基亚甲基)二氧戊环]-19-去甲孕-4-烯-3,20-二酮(外型-16;RBA = 34)。