Smith Michael J, Carvalho Humberto M, Melton-Celsa Angela R, O'Brien Alison D
Department of Microbiology and Immunology, Uniformed Services University of the Health Sciences, Room B4052, 4301 Jones Bridge Road, Bethesda, MD 20814-4799, USA.
Infect Immun. 2006 Dec;74(12):6992-8. doi: 10.1128/IAI.01247-06. Epub 2006 Oct 9.
The 13C4 monoclonal antibody (MAb) recognizes the B subunit of Stx1 (StxB1) and neutralizes the cytotoxic and lethal activities of Stx1. However, this MAb does not bind to the B polypeptide of Stx2, despite the 73% amino acid sequence similarity between StxB1 and StxB2. When we compared the amino acid sequences of StxB1 and StxB2, we noted three regions of dissimilarity (amino acids 1 to 6, 25 to 32, and 54 to 61) located near each other on the crystal structure of StxB1. To identify the 13C4 epitope, we generated seven Stx1/Stx2 B chimeric polypeptides that contained one, two, or three of the dissimilar StxB1 regions. The 13C4 MAb reacted strongly with StxB1 and the triple-chimeric B subunit but not with the other chimeras. Mice immunized with the triple-chimeric B subunit survived a lethal challenge with Stx1 but not Stx2, substantiating the identified regions as the 13C4 MAb epitope and suggesting that the incorporation of this epitope into StxB2 altered sites necessary for anti-Stx2-neutralizing Ab production. Next, single amino acid substitutions were made in StxB1 to mimic Stx1d, a variant not recognized by the 13C4 MAb. The 13C4 MAb reacted strongly to StxB1 with the T1A or G25A mutations but not with the N55T change. Finally, we found that the 13C4 MAb blocked the binding of Stx1 to its receptor, globotriaosyl ceramide. Taken together, these results indicate that the 13C4 MAb prevents the interaction of Stx1 with its receptor by binding three nonlinear regions of the molecule that span receptor recognition sites on StxB1, one of which includes the essential residue 55N.
13C4单克隆抗体(MAb)可识别Stx1的B亚基(StxB1),并中和Stx1的细胞毒性和致死活性。然而,尽管StxB1与Stx2的氨基酸序列相似度达73%,但该单克隆抗体并不与Stx2的B多肽结合。当我们比较StxB1和Stx2的氨基酸序列时,注意到在StxB1的晶体结构上彼此相邻的三个不同区域(氨基酸1至6、25至32和54至61)。为了确定13C4表位,我们生成了七种Stx1/Stx2 B嵌合多肽,它们包含一个、两个或三个不同的StxB1区域。13C4单克隆抗体与StxB1和三嵌合B亚基强烈反应,但不与其他嵌合体反应。用三嵌合B亚基免疫的小鼠在接受Stx1致死性攻击后存活,但接受Stx2攻击则不能存活,这证实了所确定的区域为13C4单克隆抗体表位,并表明将该表位掺入StxB2会改变产生抗Stx2中和抗体所需的位点。接下来,在StxB1中进行单个氨基酸替换以模拟Stx1d,这是一种不被13C4单克隆抗体识别的变体。13C4单克隆抗体对具有T1A或G25A突变的StxB1强烈反应,但对N55T变化则无反应。最后,我们发现13C4单克隆抗体可阻断Stx1与其受体球三糖基神经酰胺的结合。综上所述,这些结果表明,13C4单克隆抗体通过结合分子的三个非线性区域来阻止Stx1与其受体相互作用,这三个区域跨越StxB1上的受体识别位点,其中一个区域包括必需残基55N。