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一种含有铂(II)配合物且以N-烷基联吡啶鎓配体作为轴组件的[2]轮烷的不可逆和可逆形成。

Irreversible and reversible formation of a [2]rotaxane containing platinum(II) complex with an N-alkyl bipyridinium ligand as the axis component.

作者信息

Suzaki Yuji, Taira Toshiaki, Osakada Kohtaro

机构信息

Chemical Resources Laboratory R1-3, Tokyo Institute of Technology, 4259 Nagatsuta, Midori-ku, Yokohama, 226-8503, Japan.

出版信息

Dalton Trans. 2006 Dec 7(45):5345-51. doi: 10.1039/b610087b. Epub 2006 Oct 25.

Abstract

An N-Alkyl bipyridinium having a polymethylene chain and a bulky aryl group at the end, [4,4'-bpy-N-(CH2)10OC6H(3)-3,5-tBu2]Cl (Cl), reacts with K[PtCl3(dmso)] to produce the Pt complex with the N-alkyl bipyridinium ligand [Cl2(dmso)Pt{4,4'-bpy-N-(CH2)10OC6H(3)-3,5-tBu2}][PtCl3(dmso)] as a 6:1 mixture of trans and cis isomers ([trans-][PtCl3(dmso)] and [cis-][PtCl3(dmso)]). Addition of alpha-cyclodextrin (alpha-CD) to a solution of Cl in dmso-d6/D2O (3:1) forms [2]pseudorotaxane [{4,4'-bpy-N-(CH2)10OC6H(3)-3,5-tBu2}.(alpha-CD)]Cl (Cl) which is equilibrated with Cl and alpha-CD in solution. The reaction of K[PtCl3(dmso)] with Cl affords the [2]rotaxane [trans-Cl2(dmso)Pt{4,4'-bpy-N-(CH2)10OC6H(3)-3,5-tBu2}.(alpha-CD)][PtCl3(dmso)] ([trans-][PtCl3(dmso)]) which contains alpha-CD and [trans-][PtCl3(dmso)] as the cyclic and axis components, respectively. Dissolution of a mixture of [trans-][PtCl3(dmso)], [cis-][PtCl3(dmso)] and alpha-CD in dmso-d6/D2O (3:1) forms a mixture of the rotaxanes containing [trans--d6][PtCl3(dmso)] and [cis--d6][PtCl3(dmso)]. The reaction involves partial dissociation of the bipyridinium from Pt of [trans-][PtCl3(dmso)] or [cis-][PtCl3(dmso)] to yield [PtCl3(dmso)] and formation of pseudorotaxane with alpha-CD, followed by recoordination of the bipyridinium to the Pt. The reversible formation of the Pt-N coordination bond is studied in a dmso solution of the N-butyl compounds [trans-Cl2(dmso)Pt{4,4'-bpy-N-nBu}][PtCl3(dmso)] ([trans-][PtCl3(dmso)]).

摘要

一种在末端具有聚亚甲基链和庞大芳基的N-烷基联吡啶鎓盐,[4,4'-联吡啶-N-(CH2)10OC6H(3)-3,5-二叔丁基]氯(Cl),与K[PtCl3(dmso)]反应生成具有N-烷基联吡啶鎓配体的铂配合物[Cl2(dmso)Pt{4,4'-联吡啶-N-(CH2)10OC6H(3)-3,5-二叔丁基}][PtCl3(dmso)],为反式和顺式异构体的6:1混合物([反式-][PtCl3(dmso)]和[顺式-][PtCl3(dmso)])。向Cl在氘代二甲亚砜/重水(3:1)中的溶液中加入α-环糊精(α-CD),形成[2]准轮烷[{4,4'-联吡啶-N-(CH2)10OC6H(3)-3,5-二叔丁基}·(α-CD)]氯(Cl),其在溶液中与Cl和α-CD处于平衡状态。K[PtCl3(dmso)]与Cl反应得到[2]轮烷[反式-Cl2(dmso)Pt{4,4'-联吡啶-N-(CH2)10OC6H(3)-3,5-二叔丁基}·(α-CD)][PtCl3(dmso)]([反式-][PtCl3(dmso)]),其分别包含α-CD和[反式-][PtCl3(dmso)]作为环状和轴状组分。将[反式-][PtCl3(dmso)]、[顺式-][PtCl3(dmso)]和α-CD的混合物溶解在氘代二甲亚砜/重水(3:1)中,形成含有[反式-d6][PtCl3(dmso)]和[顺式-d6][PtCl3(dmso)]的轮烷混合物。该反应涉及[反式-][PtCl3(dmso)]或[顺式-][PtCl3(dmso)]中铂上的联吡啶鎓部分解离生成[PtCl3(dmso)],并与α-CD形成准轮烷,随后联吡啶鎓重新配位到铂上。在N-丁基化合物[反式-Cl2(dmso)Pt{4,4'-联吡啶-N-正丁基}][PtCl3(dmso)]([反式-][PtCl3(dmso)])的二甲亚砜溶液中研究了Pt-N配位键的可逆形成。

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