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基于简单家系的MOD评分分析:基于似然性的连锁分析方法概述

MOD-score analysis with simple pedigrees: an overview of likelihood-based linkage methods.

作者信息

Strauch Konstantin

机构信息

Institute of Medical Biometry and Epidemiology, Philipps University Marburg, Marburg, Germany.

出版信息

Hum Hered. 2007;64(3):192-202. doi: 10.1159/000102992. Epub 2007 May 25.

Abstract

A MOD-score analysis, in which the parametric LOD score is maximized with respect to the trait-model parameters, can be a powerful method for the mapping of complex traits. With affected sib pairs, it has been shown before that MOD scores asymptotically follow a mixture of chi(2) distributions with 2, 1 and 0 degrees of freedom under the null hypothesis of no linkage. In that context, a MOD-score analysis yields some (albeit limited) information regarding the trait-model parameters, and there is a chance for an increased power compared to a simple LOD-score analysis. Here, it is shown that with unilineal affected relative pairs, MOD scores asymptotically follow a mixture of chi(2) distributions with 1 and 0 degrees of freedom under the null hypothesis, that is, the same distribution as followed by simple LOD scores. No information regarding the trait model can be obtained in this setting, and no power is gained when compared to a LOD-score analysis. An outlook to larger pedigrees is given. The number of degrees of freedom underlying the null distribution of MOD scores, that depends on the type of pedigrees studied, corresponds to the number of explored dimensions related to power and to the number of parameters that can jointly be estimated.

摘要

一种MOD分数分析方法,即参数化LOD分数相对于性状模型参数最大化,可能是用于复杂性状定位的一种强大方法。对于患病同胞对,之前已经表明,在无连锁的零假设下,MOD分数渐近地遵循自由度为2、1和0的卡方分布的混合。在这种情况下,MOD分数分析会产生一些(尽管有限)关于性状模型参数的信息,并且与简单的LOD分数分析相比,存在提高检验效能的可能性。在此表明,对于单系患病亲属对,在零假设下,MOD分数渐近地遵循自由度为1和0的卡方分布的混合,也就是说,与简单LOD分数所遵循的分布相同。在这种情况下无法获得关于性状模型的任何信息,并且与LOD分数分析相比,检验效能没有提高。还给出了对更大系谱的展望。MOD分数零分布所基于的自由度数量取决于所研究系谱的类型,它对应于与检验效能相关的探索维度数量以及可以联合估计的参数数量。

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