Pan J L
Opt Lett. 2000 Mar 15;25(6):369-71. doi: 10.1364/ol.25.000369.
Published works have predicted that the radiative transfer from a heated metal to a lossless dielectric a short distance away is many orders of magnitude times the free-space Planck density. It is shown analytically that the radiative transfer from a heated metal to a lossless dielectric of index n(3) is n(3)(2)e(13) times the free-space Planck density, where e(13) is the emissivity of the metal radiating into the lossless dielectric. This radiative transfer is never larger than n(3)(2) (approximately one order of magnitude for semiconductors in the infrared) times the free=space Planck density. The expressions presented show that the maximum radiative transfer from a lossy metallic heat source with a dielectric function of imaginary part ?(I) must be proportional to n(3)(3)/ radical?(I), of which a factor of n(3)(2) arises from the power density within a dielectric and a factor of n(3)/ radical?(I) arises from the emissivity of a metal radiating directly into a dielectric.
已发表的研究成果预测,从加热的金属到距离其不远的无损电介质的辐射传输比自由空间普朗克密度大许多个数量级。分析表明,从加热的金属到折射率为n(3)的无损电介质的辐射传输是自由空间普朗克密度的n(3)(2)e(13)倍,其中e(13)是金属向无损电介质辐射的发射率。这种辐射传输永远不会大于n(3)(2)(对于红外波段的半导体,大约为一个数量级)乘以自由空间普朗克密度。给出的表达式表明,具有虚部为?(I)的介电函数的有损金属热源的最大辐射传输必须与n(3)(3)/√?(I)成正比,其中n(3)(2)这一因子源于电介质内的功率密度,而n(3)/√?(I)这一因子源于直接向电介质辐射的金属的发射率。