Fan Wei, Zhang R Q, Rocha A Reily, Sanvito Stefano
Nano-organic Photoelectronic Laboratory, Technical Institute of Physics and Chemistry, Chinese Academy of Sciences, Beijing 100190, China.
J Chem Phys. 2008 Aug 21;129(7):074710. doi: 10.1063/1.2971176.
Hybridization in aromatic molecules plays an important role in determining their electron transport properties. When an sp(2) bonded aromatic ring hybridizes with a carbon pair in either sp(3), sp(2), or sp form, only sp(2) and sp result in a delocalized state across the whole molecule, opening a channel for transport. At the same time negative differential resistance (NDR) is found only in the sp(2) and sp cases. An energy alignment scheme is adopted to elucidate the NDR process. This is constructed by comparing the positions of frontier molecular levels and the states of leads. It is revealed that the alignment between lead states located around the Fermi energy with the lowest unoccupied molecular orbital of the central molecule is the main cause of the NDR.
芳香分子中的杂化在决定其电子传输特性方面起着重要作用。当一个以sp(2)键合的芳香环与处于sp(3)、sp(2)或sp形式的碳对发生杂化时,只有sp(2)和sp杂化会导致整个分子处于离域状态,从而打开一个传输通道。同时,仅在sp(2)和sp杂化的情况下发现了负微分电阻(NDR)。采用一种能量对齐方案来阐明NDR过程。这是通过比较前沿分子能级的位置和引线的状态构建的。结果表明,位于费米能量附近的引线状态与中心分子的最低未占据分子轨道之间的对齐是NDR的主要原因。