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将单个病例与对照样本进行比较:校正与进一步评论。

Comparing a single case with a control sample: correction and further comment.

作者信息

Corballis Michael C

机构信息

Department of Psychology, University of Auckland, Auckland 1142, New Zealand.

出版信息

Neuropsychologia. 2009 Nov;47(13):2696-7. doi: 10.1016/j.neuropsychologia.2009.04.012. Epub 2009 Apr 19.

Abstract

Crawford, Garthwaite and Howell [Crawford, J. R., Garthwaite, P. H., & Howell, D. C. On comparing a single case with a control sample: An alternative perspective. Neuropsychologia, in press] correctly point out that the t-test I suggested for asking whether a single case belongs in the population from which a control sample is drawn is incorrect. In fact, the corrected formula can be interpreted either as addressing this question, or as asking whether the single case and the control sample are drawn from populations with the same mean. Extension to analysis of variance is recommended for factorial experiments, where single case and control sample are tested under different experimental conditions. It is not recommended for studies in which different tests are administered and treated as different levels of the same dependent variable, as in tests for neuropsychological dissociations.

摘要

克劳福德、加思韦特和豪厄尔[克劳福德,J.R.,加思韦特,P.H.,&豪厄尔,D.C.关于将单个病例与对照样本进行比较:另一种视角。《神经心理学》,即将发表]正确地指出,我所建议的用于询问单个病例是否属于抽取对照样本的总体的t检验是不正确的。事实上,校正后的公式既可以解释为解决这个问题,也可以解释为询问单个病例和对照样本是否来自均值相同的总体。对于析因实验,建议将其扩展到方差分析,在析因实验中,单个病例和对照样本在不同的实验条件下进行测试。对于像神经心理学分离测试那样,进行不同测试并将其视为同一因变量的不同水平的研究,不建议这样做。

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