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(dpp-Bian)Sm(dme)3 的单电子和双电子转移反应。

One- and two-electron-transfer reactions of (dpp-Bian)Sm(dme)3.

机构信息

G. A. Razuvaev Institute of Organometallic Chemistry, Russian Academy of Sciences, Tropinina 49, Nizhny Novgorod 603600, Russia.

出版信息

Inorg Chem. 2010 Mar 15;49(6):2901-10. doi: 10.1021/ic902439x.

Abstract

The reduction of 1,2-bis[(2,6-diisopropylphenyl)imino]acenaphthene (dpp-Bian) with an excess of samarium in 1,2-dimethoxyethane (dme) affords the Sm(II) complex (dpp-Bian)Sm(dme)(3) (1). The reaction of 1 with 0.5 mol equiv of 1,2-dibromostilbene proceeds with the formation of the dimeric Sm(III) complex (dpp-Bian)SmBr(dme) (2). Oxidation of both the metal and the dpp-Bian ligand takes place if 1 is reacted with equimolar amounts of 1,2-dibromostilbene or iodine, yielding the monomeric Sm(III) derivatives (dpp-Bian)SmBr(2)(dme) (3) and (dpp-Bian)SmI(2)(THF)(2) (4; THF = tetrahydrofuran), respectively. The reaction of 1 with 0.5 mol equiv of iodine followed by 0.5 mol equiv of tetramethylthiuram disulfide gives the Sm(III) complex (dpp-Bian)SmISC(S)NMe(2) (5). Compound 4 and tBuOK react with the formation of the iodine-bridged dimer (dpp-Bian)SmI(OtBu)(THF) (6). Complexes 1 and 2 have been characterized by (1)H NMR spectroscopy and complexes 2-6 by their molecular structures, which were determined by single-crystal X-ray diffraction.

摘要

1,2-双[(2,6-二异丙基苯基)亚氨基]吖啶(dpp-Bian)与过量钐在 1,2-二甲氧基乙烷(dme)中还原得到 Sm(II)配合物(dpp-Bian)Sm(dme)(3)(1)。1 与 0.5 mol 当量的 1,2-二溴二苯乙烯反应生成二聚 Sm(III)配合物(dpp-Bian)SmBr(dme)(2)。如果 1 与等摩尔量的 1,2-二溴二苯乙烯或碘反应,金属和 dpp-Bian 配体都会发生氧化,分别得到单体 Sm(III)衍生物(dpp-Bian)SmBr(2)(dme)(3)和(dpp-Bian)SmI(2)(THF)(2)(4;THF = 四氢呋喃)。1 与 0.5 mol 当量的碘反应,然后与 0.5 mol 当量的四甲基秋兰姆二硫化物反应,得到 Sm(III)配合物(dpp-Bian)SmISC(S)NMe(2)(5)。化合物 4 和 tBuOK 反应生成碘桥联二聚体(dpp-Bian)SmI(OtBu)(THF)(6)。配合物 1 和 2 通过(1)H NMR 光谱进行了表征,配合物 2-6 通过其分子结构进行了表征,这些结构通过单晶 X 射线衍射确定。

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