Dri A M, Rouviere-Yaniv J, Moreau P L
Enzymologie, Centre National de la Recherche Scientifique, Gif-sur-Yvette, France.
J Bacteriol. 1991 May;173(9):2852-63. doi: 10.1128/jb.173.9.2852-2863.1991.
Escherichia coli hupA hypB double mutants that lack HU protein have severe cellular defects in cell division, DNA folding, and DNA partitioning. Here we show that the sfiA11 mutation, which alters the SfiA cell division inhibitor, reduces filamentation and production of anucleate cells in AB1157 hupA hupB strains. However, lexA3(Ind-) and sfiB(ftsZ)114 mutations, which normally counteract the effect of the SfiA inhibitor, could not restore a normal morphology to hupA hupB mutant bacteria. The LexA repressor, which controls the expression of the sfiA gene, was present in hupA hupB mutant bacteria in concentrations half of those of the parent bacteria, but this decrease was independent of the specific cleavage of the LexA repressor by activated RecA protein. One possibility to account for the filamentous morphology of hupA hupB mutant bacteria is that the lack of HU protein alters the expression of specific genes, such as lexA and fts cell division genes.
缺乏HU蛋白的大肠杆菌hupA hypB双突变体在细胞分裂、DNA折叠和DNA分配方面存在严重的细胞缺陷。我们在此表明,改变SfiA细胞分裂抑制剂的sfiA11突变可减少AB1157 hupA hupB菌株中的丝状体形成和无核细胞的产生。然而,通常可抵消SfiA抑制剂作用的lexA3(Ind-)和sfiB(ftsZ)114突变,无法使hupA hupB突变细菌恢复正常形态。控制sfiA基因表达的LexA阻遏物在hupA hupB突变细菌中的浓度是亲本细菌的一半,但这种降低与活化的RecA蛋白对LexA阻遏物的特异性切割无关。解释hupA hupB突变细菌丝状形态的一种可能性是,HU蛋白的缺乏改变了特定基因的表达,如lexA和fts细胞分裂基因。