Division of Pediatric Surgery, St. Louis Children's Hospital, Washington University School of Medicine, St. Louis, MO 63110, USA.
J Pediatr Surg. 2010 Jun;45(6):1274-9. doi: 10.1016/j.jpedsurg.2010.02.101.
The magnitude of intestinal adaptation is considered to correlate with the extent of small bowel resection (SBR). However, this association has never been tested in mice. We sought to test the hypothesis that a greater SBR will induce a greater adaptation response.
C57/B6 mice underwent 50% SBR, 75% SBR, or sham operation and were killed on postoperative day 7. The magnitude of adaptation was compared between 50% SBR and 75% SBR as changes in villus height, crypt depth, as well as rates of apoptosis and proliferation.
Seventy-five percent SBR led to decreased survival and increased weight loss compared with 50% SBR. The remnant ileum of both 50% SBR and 75% SBR displayed similar crypt expansion, enhanced villi, and increased apoptotic indices. Proliferation rates increased after 50% and 75% SBR equally.
Models of resection greater than 50% in mice result in greater morbidity and mortality and do not magnify the adaptation response to massive SBR. The use of more extreme resection models does not appear to provide added benefit for investigating mechanisms of intestinal adaptation.
肠适应的程度被认为与小肠切除(SBR)的范围相关。然而,这种关联从未在小鼠中进行过测试。我们试图验证这样一个假设,即更大的 SBR 将引起更大的适应反应。
C57/B6 小鼠接受 50%的 SBR、75%的 SBR 或假手术,并在术后第 7 天处死。通过比较绒毛高度、隐窝深度的变化以及凋亡和增殖率,比较 50%的 SBR 和 75%的 SBR 之间适应的程度。
与 50%的 SBR 相比,75%的 SBR 导致存活率降低和体重减轻增加。50%和 75%的 SBR 都会导致残余回肠的隐窝扩张、绒毛增强和凋亡指数增加。50%和 75%的 SBR 后增殖率同样增加。
在小鼠中,大于 50%的切除模型会导致更高的发病率和死亡率,并且不会放大对大量 SBR 的适应反应。使用更极端的切除模型似乎并不能为研究肠适应的机制提供额外的好处。