Department of Pathology and Immunology, Washington University School of Medicine, St. Louis, MO 63110, USA.
Mol Cell Biol. 2010 Nov;30(21):5043-56. doi: 10.1128/MCB.01472-09. Epub 2010 Aug 23.
Par-1 is an evolutionarily conserved protein kinase required for polarity in worms, flies, frogs, and mammals. The mammalian Par-1 family consists of four members. Knockout studies of mice implicate Par-1b/MARK2/EMK in regulating fertility, immune homeostasis, learning, and memory as well as adiposity, insulin hypersensitivity, and glucose metabolism. Here, we report phenotypes of mice null for a second family member (Par-1a/MARK3/C-TAK1) that exhibit increased energy expenditure, reduced adiposity with unaltered glucose handling, and normal insulin sensitivity. Knockout mice were protected against high-fat diet-induced obesity and displayed attenuated weight gain, complete resistance to hepatic steatosis, and improved glucose handling with decreased insulin secretion. Overnight starvation led to complete hepatic glycogen depletion, associated hypoketotic hypoglycemia, increased hepatocellular autophagy, and increased glycogen synthase levels in Par-1a(-/-) but not in control or Par-1b(-/-) mice. The intercrossing of Par-1a(-/-) with Par-1b(-/-) mice revealed that at least one of the four alleles is necessary for embryonic survival. The severity of phenotypes followed a rank order, whereby the loss of one Par-1b allele in Par-1a(-/-) mice conveyed milder phenotypes than the loss of one Par-1a allele in Par-1b(-/-) mice. Thus, although Par-1a and Par-1b can compensate for one another during embryogenesis, their individual disruption gives rise to distinct metabolic phenotypes in adult mice.
Par-1 是一种进化上保守的蛋白激酶,在蠕虫、苍蝇、青蛙和哺乳动物中都需要它来维持极性。哺乳动物 Par-1 家族由四个成员组成。对小鼠的敲除研究表明,Par-1b/MARK2/EMK 在调节生育、免疫稳态、学习和记忆以及肥胖、胰岛素敏感性和葡萄糖代谢方面发挥作用。在这里,我们报告了第二种家族成员(Par-1a/MARK3/C-TAK1)缺失的小鼠表型,这些表型表现出能量消耗增加、脂肪减少但葡萄糖处理不变以及胰岛素敏感性正常。敲除小鼠对高脂肪饮食诱导的肥胖具有保护作用,表现出体重增加减少、完全抵抗肝脂肪变性以及改善葡萄糖处理而胰岛素分泌减少。 overnight starvation 导致完全肝糖原耗竭,伴有低酮血症低血糖症、肝细胞自噬增加和糖原合酶水平升高,但在 Par-1a(-/-)小鼠中而非在对照或 Par-1b(-/-)小鼠中。Par-1a(-/-)与 Par-1b(-/-)小鼠的杂交表明,至少有一个 Par-1b 等位基因对于胚胎存活是必要的。表型的严重程度遵循一个等级顺序,即 Par-1a(-/-)小鼠中一个 Par-1b 等位基因的缺失比 Par-1b(-/-)小鼠中一个 Par-1a 等位基因的缺失传递出更温和的表型。因此,尽管 Par-1a 和 Par-1b 在胚胎发生期间可以相互补偿,但它们的单独缺失会导致成年小鼠产生不同的代谢表型。