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苯胺的单电子氧化和单电子还原的后果。

Consequence of one-electron oxidation and one-electron reduction for aniline.

机构信息

Department of Chemistry, Warsaw University of Life Sciences (SGGW), ul. Nowoursynowska 159c, 02-776 Warszawa, Poland.

出版信息

J Mol Model. 2011 Dec;17(12):3229-39. doi: 10.1007/s00894-011-1001-z. Epub 2011 Mar 4.

Abstract

Quantum-chemical calculations were performed for all possible isomers of neutral aniline and its redox forms, and intramolecular proton-transfer (prototropy) accompanied by π-electron delocalization was analyzed. One-electron oxidation (PhNH(2) - e → PhNH(2)) has no important effect on tautomeric preferences. The enamine tautomer is preferred for oxidized aniline similarly as for the neutral molecule. Dramatical changes take place when proceeding from neutral to reduced aniline. One-electron reduction (PhNH(2) + e → PhNH(2)) favors the imine tautomer. Independently on the state of oxidation, π- and n-electrons are more delocalized for the enamine than imine tautomers. The change of the tautomeric preferences for reduced aniline may partially explain the origin of the CH tautomers for reduced nucleobases (cytosine, adenine, and guanine).

摘要

对中性苯胺及其氧化还原形式的所有可能异构体进行了量子化学计算,并分析了伴随π电子离域的分子内质子转移(互变异构)。单电子氧化(PhNH(2) - e ⁇ PhNH(2)](+•))对互变异构偏好没有重要影响。对于氧化苯胺,烯胺互变异构体与中性分子一样是首选的。当从中性苯胺向还原苯胺进行时,会发生剧烈的变化。单电子还原(PhNH(2) ⁇ PhNH(2)](-•)有利于亚胺互变异构体。无论氧化状态如何,π电子和 n 电子对于烯胺互变异构体比亚胺互变异构体更具离域性。对于还原苯胺的互变异构偏好的变化可能部分解释了还原碱基(胞嘧啶、腺嘌呤和鸟嘌呤)的 CH 互变异构体的起源。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/7a6f/3224217/d953522a9b1c/894_2011_1001_Sch1_HTML.jpg

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