Department of Chemistry, Graduate School of Science, Osaka Prefecture University, Sakai, Osaka, Japan.
Org Biomol Chem. 2011 May 21;9(10):3780-6. doi: 10.1039/c1ob05145h. Epub 2011 Apr 12.
Tin hydride mediated radical carbonylation and cyclization reaction was investigated using a variety of ω-alkynyl amines as substrates. In this reaction α-methylene and α-stannylmethylene lactams having five to eight membered rings were obtained as principal products. In cases where the nitrogen has a substituent capable of giving stable radicals, such as an α-phenethyl group, the lactam ring formation again took place with extrusion of an α-phenethyl radical. Coupled with the subsequent protodestannylation procedure (TMSCl plus MeOH), these reactions provide a useful entry to α-methylene lactams with incorporation of CO as a lactam carbonyl group. In cases where the amines do not have a substituent acting as a radical leaving group, a reaction course involving a 1,4-H shift is chosen so as to liberate tin radicals ultimately. Thus the proposed mechanism involves (i) nucleophilic attack of amine nitrogen onto a carbonyl group of α,β-unsaturated acyl radicals/α-ketenyl radicals via lone pair-π* interaction, which leads to zwitterionic radical species, (ii) the subsequent proton shift from N to O to give hydroxyallyl radicals, (iii) 1,4-hydrogen shift from O to C, and (iv) β-scission to give lactams with liberation of tin radicals. DFT calculations reveal that the 1,4-hydrogen shifts, the key step of the reaction mechanism, can proceed under usual reaction conditions. On the other hand, an S(H)i type reaction to give lactams may be the result of the β-scission of the similar zwitterionic radical intermediates. DFT calculations also predict that an S(H)i type reaction would result when the intermediate has a good (radical) leaving group such as a phenethyl group.
四氢锡介导的自由基羰化环化反应研究了各种ω-炔基胺作为底物。在该反应中,主要得到具有五至八个环的α-亚甲基和α-锡亚甲基内酰胺。在氮原子具有能够形成稳定自由基的取代基的情况下,例如α-苯乙基,再次发生内酰胺环形成,同时挤出α-苯乙基自由基。与随后的脱锡氢(TMSCl 加甲醇)程序相结合,这些反应提供了一种有用的方法,将 CO 作为内酰胺羰基引入到α-亚甲基内酰胺中。在胺没有作为自由基离去基团的取代基的情况下,选择涉及 1,4-H 转移的反应途径,最终释放锡自由基。因此,所提出的机制包括(i)通过孤对-π*相互作用,胺氮亲核攻击α,β-不饱和酰基自由基/α-烯基自由基的羰基,导致两性离子自由基物种,(ii)随后从 N 到 O 的质子转移,生成羟烯丙基自由基,(iii)从 O 到 C 的 1,4-氢转移,以及(iv)β-断裂,生成释放锡自由基的内酰胺。DFT 计算表明,1,4-氢转移是反应机制的关键步骤,可以在通常的反应条件下进行。另一方面,通过 S(H)i 型反应生成内酰胺可能是类似两性离子自由基中间体β-断裂的结果。DFT 计算还预测,当中间体具有良好的(自由基)离去基团(如苯乙基)时,S(H)i 型反应会发生。