Hao Cheng-Jun, Zhang Yan-Hua
Acta Crystallogr Sect E Struct Rep Online. 2010 Apr 17;66(Pt 5):o1089. doi: 10.1107/S1600536810013073.
The asymmetric unit of the title compound, C(22)H(42)N(6)·2CH(4)O, comprises one half of a 14-membered tetra-azacyclo-tetra-decane macrocycle with cyano-ethyl substituents on one of the N atoms and a methanol solvent mol-ecule. The macrocycle lies about an inversion centre. The cyano-ethyl substituents are oriented so that the cyano groups lie over opposite faces of the central cavity of the macrocycle. The methanol solvate mol-ecules lie away from the cavity of the macrocycle and are linked to the macrocycles via O-H⋯N hydrogen bonds.
标题化合物C(22)H(42)N(6)·2CH(4)O的不对称单元包含一个14元四氮杂环十四烷大环的一半,其中一个氮原子上带有氰基乙基取代基以及一个甲醇溶剂分子。大环位于一个对称中心上。氰基乙基取代基的取向使得氰基位于大环中心腔的相对面上。甲醇溶剂分子远离大环的腔,并通过O—H⋯N氢键与大环相连。