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5-氯-N-[2-(1H-咪唑-4-基)乙基]-N-甲基-7H-吡咯并[2,3-d]嘧啶-4-胺

5-Chloro-N-[2-(1H-imidazol-4-yl)eth-yl]-N-methyl-7H-pyrrolo[2,3-d]pyrimidin-4-amine.

作者信息

Richter Daniel, Kath John C, Rheingold Arnold L, Dipasquale Antonio, Yanovsky Alex

出版信息

Acta Crystallogr Sect E Struct Rep Online. 2009 Dec 24;66(Pt 1):o242. doi: 10.1107/S1600536809054750.

DOI:10.1107/S1600536809054750
PMID:21580123
原文链接:https://pmc.ncbi.nlm.nih.gov/articles/PMC2980157/
Abstract

The title compound, C(12)H(13)ClN(6), was prepared by reaction of 4,5-dichloro-7H-pyrrolo[2,3-d]pyrimidine with 2-(1H-imid-azol-4-yl)-N-methyl-ethanamine, and the X-ray study confirmed that chloro-substituent in six-membered ring was replaced in the reaction. The exocyclic N atom environment is approximately coplanar with the pyrrolo[2,3-d]pyrimidine [corresponding dihedral angle is 5.5 (1)°], whereas the mean plane of the N-C-C-C link connecting with the imidazolyl ring is almost exactly orthogonal to the plane of the bicyclic system [dihedral angle = 91.6 (2)°]. The imidazolyl plane itself, however, forms a relatively small dihedral angle of 20.8 (1)° with the pyrrolo[2,3-d]pyrimidine plane. There are two independent N-H⋯N hydrogen bonds in the structure, which link mol-ecules into layers parallel to (03).

摘要

标题化合物C(12)H(13)ClN(6)是通过4,5-二氯-7H-吡咯并[2,3-d]嘧啶与2-(1H-咪唑-4-基)-N-甲基乙胺反应制备的,X射线研究证实六元环中的氯取代基在反应中被取代。环外N原子环境与吡咯并[2,3-d]嘧啶大致共面[相应的二面角为5.5 (1)°],而与咪唑环相连的N-C-C-C链的平均平面几乎与双环体系的平面完全正交[二面角 = 91.6 (2)°]。然而,咪唑平面本身与吡咯并[2,3-d]嘧啶平面形成相对较小的20.8 (1)°二面角。结构中有两个独立的N-H⋯N氢键,它们将分子连接成平行于(03)的层。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/218f/2980157/e500d72c9d31/e-66-0o242-fig2.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/218f/2980157/a6bf13cac09a/e-66-0o242-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/218f/2980157/e500d72c9d31/e-66-0o242-fig2.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/218f/2980157/a6bf13cac09a/e-66-0o242-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/218f/2980157/e500d72c9d31/e-66-0o242-fig2.jpg

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