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八水合六水合镍(II)四水双(μ-吡啶-2,6-二羧酸根)双(吡啶-2,6-二羧酸根)三镍(II)酸盐

Hexaaqua-nickel(II) tetra-aqua-bis-(μ-pyridine-2,6-dicarboxyl-ato)bis-(pyridine-2,6-dicarboxyl-ato)trinickelate(II) octa-hydrate.

作者信息

Safaei-Ghomi Javad, Motieiyan Elham, Manteghi Faranak, Ghadermazi Mohammad, Aghabozorg Hossein

出版信息

Acta Crystallogr Sect E Struct Rep Online. 2010 Jul 24;66(Pt 8):m1016-7. doi: 10.1107/S1600536810028977.

Abstract

The title compound, [Ni(H(2)O)(6)][Ni(3)(C(7)H(3)NO(4))(4)(H(2)O)(4)]·8H(2)O, was obtained by the reaction of nickel(II) nitrate hexa-hydrate with pyridine-2,6-dicarb-oxy-lic acid (pydcH(2)) and 1,10-phenanothroline (phen) in an aqueous solution. The latter ligand is not involved in formation of the title complex. There are three different Ni(II) atoms in the asymmetric unit, two of which are located on inversion centers, and thus the Ni(H(2)O)(6) cation and the trinuclear {Ni(pydc)(2)-μ-Ni(H(2)O)(4)}(2-) anion are centrosymmetric. All Ni(II) atoms exhibit an octa-hedral coordination geometry. Various inter-actions, including numerous O-H⋯O and C-H⋯O hydrogen bonds and C-O⋯π stacking of the pyridine and carboxyl-ate groups [3.570 (1), 3.758 (1) and 3.609 (1) Å], are observed in the crystal structure.

摘要

标题化合物[Ni(H₂O)₆][Ni₃(C₇H₃NO₄)₄(H₂O)₄]·8H₂O是通过六水合硝酸镍与吡啶-2,6-二羧酸(pydcH₂)和1,10-菲咯啉(phen)在水溶液中反应得到的。后一种配体不参与标题配合物的形成。不对称单元中有三个不同的Ni(II)原子,其中两个位于对称中心上,因此[Ni(H₂O)₆]²⁺阳离子和三核{[Ni(pydc)₂]²⁻-μ-Ni(H₂O)₄}²⁻阴离子是中心对称的。所有Ni(II)原子均呈现八面体配位几何构型。在晶体结构中观察到了各种相互作用,包括大量的O—H⋯O和C—H⋯O氢键以及吡啶和羧酸根基团的C—O⋯π堆积[3.570 (1)、3.758 (1)和3.609 (1) Å]。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/bb6d/3007465/1b8f40fc90a6/e-66-m1016-fig1.jpg

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