Department of Biomedical Engineering, I-SHOU University, Kaohsiung 840, Taiwan, Republic of China.
J Comput Chem. 2011 Oct;32(13):2783-99. doi: 10.1002/jcc.21858. Epub 2011 Jun 30.
The electric dipole moment p(r) was computed as the integral of the permanent dipole moment of the solvent molecule μ(r) weighted by the orientational probability distribution Ω(r;O) over all orientations, where O is the orientation of the solvent molecule at r. The relationship between Ω(r;O) and the potential of the mean torque was derived; p(r) is proportional to the electric field E(r) under the following assumptions: (1) the van der Waals (vdW) interaction is independent of the orientation of the solvent molecule at r; (2) the solvent molecule and its electrical effect are modeled as a point dipole moment; (3) the solvent molecule at r is in a region far from the solute; and (4) μE(r) ≪ k(B) T, where k(B) is Boltzmann's constant and T is absolute temperature. The errors caused by calculating near-solute Ω(r) and p(r) from E(r) are unclear. The results show that Ω(r) is inconsistent with the value calculated from E(r) for water molecules in the first and second shells of solute with charge state Q = ±1 e, and a large variation in solvent molecular polarizability γ(mol) (r), which appeared in the first valley of 4πr(2) E(r) for |Q| < 1 e. Nonetheless, p(r) is consistent with the values calculated from E(r) for |Q| ≤ 1 e. The implication is that the assumptions for calculating p(r) can be ignored in the calculation of the solvation free energy of biomolecules, as they pertain to protein folding and protein-protein/ligand interactions.
电偶极矩 p(r) 是通过将溶剂分子的永久偶极矩 μ(r) 乘以所有取向的取向概率分布 Ω(r;O) 进行积分而计算得出的,其中 O 是溶剂分子在 r 处的取向。导出了 Ω(r;O) 与平均力矩势能之间的关系;在以下假设下,p(r) 与电场 E(r) 成正比:(1) 范德华 (vdW) 相互作用与溶剂分子在 r 处的取向无关;(2) 溶剂分子及其电效应被建模为点偶极矩;(3) r 处的溶剂分子处于远离溶质的区域;以及 (4) μE(r)≪k(B)T,其中 k(B) 是玻尔兹曼常数,T 是绝对温度。由于从 E(r) 计算近溶质 Ω(r) 和 p(r) 而导致的误差尚不清楚。结果表明,对于电荷状态为 Q = ±1e 的溶质的第一和第二壳层中的水分子,Ω(r) 与从 E(r) 计算的值不一致,并且溶剂分子极化率 γ(mol)(r) 发生了很大变化,出现在|Q| < 1e 的 4πr(2)E(r) 的第一个谷中。尽管如此,p(r) 与从 E(r) 计算的值一致,对于 |Q|≤1e。这意味着在计算生物分子的溶剂化自由能时,可以忽略计算 p(r) 的假设,因为它们与蛋白质折叠和蛋白质-蛋白质/配体相互作用有关。