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双(μ-十六烷酸根-κO:O)双[(2,2'-联吡啶-κN,N')(十六烷酸根-κO)铜(II)]甲醇溶剂合物

Bis(μ-hexa-deca-noato-κO:O)bis-[(2,2'-bipyridine-κN,N')(hexa-deca-noato-κO)copper(II)] methanol disolvate.

作者信息

Che Mat Ahmad Nazeer, Abdullah Norbani, Khaledi Hamid, Tee Jia Ti

机构信息

Department of Chemistry, University of Malaya, 50603 Kuala Lumpur, Malaysia.

出版信息

Acta Crystallogr Sect E Struct Rep Online. 2011 May 1;67(Pt 5):m599-600. doi: 10.1107/S1600536811013559. Epub 2011 Apr 16.

Abstract

The asymmetric unit of the title compound, [Cu(2)(C(16)H(31)O(2))(4)(C(10)H(8)N(2))(2)]·2CH(3)OH, contains one half-mol-ecule of the metal complex solvated by a methanol mol-ecule. In the complex, two of the metal atoms are doubly bridged by two monodentate bridging hexa-deca-noate ligands around a center of inversion. The square-pyramidal geometry around each Cu(II) ion is completed by a terminal hexa-deca-noate O atom and two N atoms from a 2,2'-bipyridine ligand. The alkyl chains of the carboxyl-ate ligands are arranged in a parallel manner with an all-trans conformation. In the crystal, a π-π inter-action formed by the bipyridine rings [centroid-centroid separation = 3.7723 (17) Å] and inter-molecular C-H⋯O hydrogen bonds link the complex mol-ecules into infinite chains along the b axis. An O-H⋯O interaction between the methanol solvate and one of the carboxylate O atoms is also observed.

摘要

标题化合物[Cu₂(C₁₆H₃₁O₂)₄(C₁₀H₈N₂)₂]·2CH₃OH的不对称单元包含由一个甲醇分子溶剂化的半个金属配合物分子。在该配合物中,两个金属原子由两个单齿桥联十六烷酸酯配体围绕一个反演中心双桥联。每个Cu(II)离子周围的四方锥几何构型由一个末端十六烷酸酯O原子和来自2,2'-联吡啶配体的两个N原子完成。羧酸酯配体的烷基链以全反式构象平行排列。在晶体中,由联吡啶环形成的π-π相互作用[质心-质心间距 = 3.7723 (17) Å]和分子间C-H⋯O氢键将配合物分子沿b轴连接成无限链。还观察到甲醇溶剂化物与一个羧酸酯O原子之间的O-H⋯O相互作用。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/8079/3089362/d552d7ad3354/e-67-0m599-fig1.jpg

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