Department of Inorganic Chemistry, Indian Association for the Cultivation of Science, Jadavpur, Kolkata, India 700032.
J Am Chem Soc. 2011 Oct 5;133(39):15545-52. doi: 10.1021/ja204628b. Epub 2011 Sep 13.
Recently, it has been shown that heme binds to Aβ peptides which may play a major role in Alzheimer's disease (AD). This study illustrates that Aβ peptides can bind both Cu and heme cofactors at the same time. Both cofactors have unique spectroscopic and electrochemical features which are unaffected in the presence of the other, implying that they are electronically, chemically, and electrochemically uncoupled. These data clearly indicate that Cu cannot bind to three histidine residues simultaneously in Cu-Aβ complexes as previously proposed, since one of the histidines is involved in binding heme. The heme-Aβ and the heme-Cu-Aβ peptide complexes function as peroxidases. Interestingly, the Cu-Aβ complex also exhibits peroxidase activity, which may have significant implications in AD. Both Cu(+)-Aβ and heme (Fe(2+))-Aβ complexes reduce O(2) to H(2)O(2) quantitatively. Only one of the two electrons that are required for the reduction of O(2) to H(2)O(2) is derived from the reduced metal site, while the Tyr(10) residue of the native Aβ peptide donates the second electron. This Tyr(10) residue, the source of electron for the generation of partially reduced oxygen species (PROS, e.g., H(2)O(2)) is absent in rodents, which do not get affected by AD. When both heme and Cu are bound to the Aβ peptides, which is likely to happen physiologically, the amount of toxic PROS generated is maximum, implying that heme-Cu-Aβ complexes could potentially be most toxic for AD.
最近的研究表明,血红素与β淀粉样肽(Aβ)结合,这可能在阿尔茨海默病(AD)中起主要作用。本研究表明,Aβ 肽可以同时结合 Cu 和血红素辅因子。这两种辅因子具有独特的光谱和电化学特征,在存在另一种辅因子的情况下不受影响,这意味着它们在电子、化学和电化学上是解偶联的。这些数据清楚地表明,Cu 不能像以前提出的那样同时结合 Cu-Aβ 络合物中的三个组氨酸残基,因为其中一个组氨酸残基参与血红素结合。血红素-Aβ 和血红素-Cu-Aβ 肽复合物作为过氧化物酶起作用。有趣的是,Cu-Aβ 复合物也表现出过氧化物酶活性,这可能对 AD 有重要意义。Cu(+)-Aβ 和血红素(Fe(2+))-Aβ 复合物都将 O(2)定量还原为 H(2)O(2)。O(2)还原为 H(2)O(2)所需的两个电子中只有一个来自还原金属位点,而天然 Aβ 肽的 Tyr(10)残基提供第二个电子。这种 Tyr(10)残基是部分还原氧物种(例如 H(2)O(2))产生电子的来源,在不会受到 AD 影响的啮齿动物中不存在。当血红素和 Cu 都与 Aβ 肽结合时,这在生理上很可能发生,产生的有毒 PROS 量最大,这意味着血红素-Cu-Aβ 复合物可能对 AD 最具毒性。