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一个新的剪接突变导致一名葡萄牙男孩出现无白蛋白血症。

A novel splicing mutation causes analbuminemia in a Portuguese boy.

机构信息

Laboratory on Pathophysiology of Uremia, Istituto Giannina Gaslini IRCCS, Genova, Italy.

出版信息

Mol Genet Metab. 2012 Mar;105(3):479-83. doi: 10.1016/j.ymgme.2011.12.009. Epub 2011 Dec 16.

Abstract

Analbuminemia is a rare autosomal recessive disorder manifested by the absence or severe reduction of circulating serum albumin in homozygous or compound heterozygous subjects. It is an allelic heterogeneous defect, caused by a variety of mutations within the albumin gene. The analbuminemic condition was suspected in a Portuguese boy who presented with low albumin level (about 3.8 g/L) and a significant hypercholesterolemia, but with no clinical findings. The albumin gene was screened by single strand conformational polymorphism and heteroduplex analysis and submitted to direct DNA sequencing. The proband was found to be homozygous for a previously unreported G>A change at position c.1289+1, the first base of intron 10, which inactivates the strongly conserved GT dinucleotide at the 5' splice site consensus sequence of the intron. The effect of this mutation was evaluated by examining the cDNA obtained by RT-PCR from the albumin mRNA extracted from proband's leukocytes. The splicing defect results in the skipping of the preceding exon. The subsequent reading frame-shift in exon 11 produces a premature stop codon located 33 codons downstream the 5' end of the exon. This extensive cDNA alteration is responsible for the analbuminemic trait. Both parents were found to be heterozygous for the same mutation. DNA and cDNA sequence analysis established the diagnosis of congenital analbuminemia in the proband. The effects of the so far identified splice-site mutations in the albumin gene are discussed.

摘要

血清白蛋白缺乏症是一种罕见的常染色体隐性遗传疾病,表现为纯合子或复合杂合子个体中循环血清白蛋白的缺失或严重减少。它是一种等位基因异质性缺陷,由白蛋白基因内的多种突变引起。一名葡萄牙男孩被怀疑患有血清白蛋白缺乏症,其表现为低白蛋白水平(约 3.8 g/L)和明显的高胆固醇血症,但无临床发现。通过单链构象多态性和异源双链分析筛选白蛋白基因,并进行直接 DNA 测序。发现先证者为 10 号内含子第一个碱基 c.1289+1 的 G>A 变化的纯合子,该碱基位于内含子 5' 剪接位点保守 GT 二核苷酸,导致其失活。通过从先证者白细胞提取的白蛋白 mRNA 进行 RT-PCR 获得 cDNA,评估该突变的影响。剪接缺陷导致前一个外显子缺失。随后在 11 号外显子产生的移码突变导致提前出现终止密码子,位于外显子 5' 端下游 33 个密码子处。这种广泛的 cDNA 改变是导致血清白蛋白缺乏症的原因。父母均为同一突变的杂合子。DNA 和 cDNA 序列分析确立了先证者先天性血清白蛋白缺乏症的诊断。讨论了迄今为止在白蛋白基因中发现的剪接位点突变的影响。

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