Microbiology Department, The University of Georgia, Athens, Georgia, United States of America.
PLoS One. 2012;7(6):e38727. doi: 10.1371/journal.pone.0038727. Epub 2012 Jun 6.
The ability to synthesize and salvage purines is crucial for colonization by a variety of human bacterial pathogens. Helicobacter pylori colonizes the gastric epithelium of humans, yet its specific purine requirements are poorly understood, and the transport mechanisms underlying purine uptake remain unknown. Using a fully defined synthetic growth medium, we determined that H. pylori 26695 possesses a complete salvage pathway that allows for growth on any biological purine nucleobase or nucleoside with the exception of xanthosine. Doubling times in this medium varied between 7 and 14 hours depending on the purine source, with hypoxanthine, inosine and adenosine representing the purines utilized most efficiently for growth. The ability to grow on adenine or adenosine was studied using enzyme assays, revealing deamination of adenosine but not adenine by H. pylori 26695 cell lysates. Using mutant analysis we show that a strain lacking the gene encoding a NupC homolog (HP1180) was growth-retarded in a defined medium supplemented with certain purines. This strain was attenuated for uptake of radiolabeled adenosine, guanosine, and inosine, showing a role for this transporter in uptake of purine nucleosides. Deletion of the GMP biosynthesis gene guaA had no discernible effect on mouse stomach colonization, in contrast to findings in numerous bacterial pathogens. In this study we define a more comprehensive model for purine acquisition and salvage in H. pylori that includes purine uptake by a NupC homolog and catabolism of adenosine via adenosine deaminase.
合成和回收嘌呤的能力对于多种人类细菌病原体的定植至关重要。幽门螺杆菌定植于人类胃上皮细胞,但对其特定嘌呤需求知之甚少,嘌呤摄取的转运机制也不清楚。使用完全定义的合成生长培养基,我们确定 H. pylori 26695 拥有完整的回收途径,可在除黄嘌呤核苷以外的任何生物嘌呤核苷碱基或核苷上生长。在这种培养基中的倍增时间根据嘌呤源在 7 到 14 小时之间变化,次黄嘌呤、肌苷和腺苷是生长效率最高的嘌呤。使用酶测定法研究了在腺嘌呤或腺苷上生长的能力,结果表明 H. pylori 26695 细胞裂解物可使腺苷脱氨,但不能使腺嘌呤脱氨。通过突变分析,我们表明缺乏编码 NupC 同源物(HP1180)的基因的菌株在补充某些嘌呤的限定培养基中生长受到抑制。该菌株对放射性标记的腺苷、鸟苷和肌苷的摄取能力减弱,表明该转运蛋白在嘌呤核苷摄取中起作用。GMP 生物合成基因 guaA 的缺失对小鼠胃定植没有明显影响,这与许多细菌病原体的发现相反。在这项研究中,我们定义了一个更全面的 H. pylori 嘌呤获取和回收模型,包括通过 NupC 同源物摄取嘌呤和通过腺苷脱氨酶代谢腺苷。