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果糖可保护面包酵母免受过氧化物胁迫:过氧化氢酶和超氧化物歧化酶的潜在作用。

Fructose protects baker's yeast against peroxide stress: potential role of catalase and superoxide dismutase.

机构信息

Department of Biochemistry and Biotechnology, Vassyl Stefanyk Precarpathian National University, Ivano-Frankivsk, Ukraine.

出版信息

FEMS Yeast Res. 2012 Nov;12(7):761-73. doi: 10.1111/j.1567-1364.2012.00826.x. Epub 2012 Aug 6.

Abstract

The negative effects of fructose due to its chronic consumption are well documented, while short-term application of fructose is found to protect different types of cells against oxidative stress. Reactive oxygen species (ROS) are suggested to mediate both the cytotoxic and defensive effects. Here, we compare the influence of glucose and fructose on yeast under H(2)O(2)-induced stress. Under control conditions, fructose-grown comparing with glucose-grown yeast demonstrated higher metabolic activity and ROS level. Therefore, fructose was suggested to provoke a mild stress that resulted in the acquisition of cellular resistance to lethal challenges, which explained the higher survival of fructose-grown yeast under H(2)O(2)-induced shock. Exposure to H(2)O(2) increased ROS level in glucose-grown cells, whereas it decreased the ROS level in fructose-grown cells. Hydrogen peroxide activated superoxide dismutase (SOD) and catalase in both the cell types studied, but glucose-grown cells demonstrated a sharp rise of the activities, while cells grown on fructose showed a broad peak of activation. Thus, fructose is likely to protect the antioxidant enzymes against their inactivation by H(2)O(2). Despite a different type of the enzyme activation in both the studied cell types (glucose- and fructose-grown), a strong positive correlation between SOD and catalase was found. The physiological meaning of this relationship and possible mechanisms of the fructose protective effect are discussed.

摘要

由于其慢性消耗,果糖的负面影响有充分的文献记载,而短期应用果糖被发现可保护不同类型的细胞免受氧化应激。活性氧(ROS)被认为介导细胞毒性和防御作用。在这里,我们比较了葡萄糖和果糖对酵母在 H(2)O(2)诱导应激下的影响。在对照条件下,与葡萄糖生长的酵母相比,果糖生长的酵母表现出更高的代谢活性和 ROS 水平。因此,果糖被认为会引起轻微的应激,从而获得对致死性挑战的细胞抗性,这解释了在 H(2)O(2)诱导休克下果糖生长的酵母更高的存活率。暴露于 H(2)O(2)增加了葡萄糖生长细胞中的 ROS 水平,而降低了果糖生长细胞中的 ROS 水平。过氧化氢激活了两种研究细胞类型中的超氧化物歧化酶(SOD)和过氧化氢酶,但葡萄糖生长的细胞表现出活性的急剧上升,而果糖生长的细胞则表现出广泛的激活峰。因此,果糖可能会保护抗氧化酶免受 H(2)O(2)的失活。尽管在两种研究的细胞类型(葡萄糖和果糖生长)中,酶的激活类型不同,但 SOD 和过氧化氢酶之间存在很强的正相关。讨论了这种关系的生理意义和果糖保护作用的可能机制。

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