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在无溶剂条件下,以分子碘为催化剂,由酯和腈合成酰胺。

Amide synthesis from esters with nitriles under solvent-free conditions using molecular iodine as a catalyst.

作者信息

Hanzawa Yohko, Kasashima Yoshio, Tomono Kazuki, Mino Takashi, Sakamoto Masami, Fujita Tsutomu

机构信息

Education Center, Faculty of Engineering, Chiba Institute of Technology, Japan.

出版信息

J Oleo Sci. 2012;61(7):393-9. doi: 10.5650/jos.61.393.

Abstract

The reaction of esters with nitriles, using iodine as a catalyst under solvent-free conditions, was investigated. For example, 1-phenylethyl acetate reacted with benzonitrile in the presence of iodine to afford the amide, N-(1-phenylethyl)benzamide. Addition of water was effective in promoting amidation. The most suitable conditions were investigated, and determined as follows: temperature = 80°C, molar ratio of nitrile:alcohol:iodine:water = 1:3:0.2:1.0, and reaction time = 18 h. The amidation reactivity depended on the stability of the cationic intermediate formed from the ester. Only the reaction of 2-phenylpropan-2-yl acetate with benzonitrile gave no amide compound; rather, the cyclic compound, 1,1,3-trimethyl-3-phenyl-2,3-dihydro-1H-indene was obtained in 90% yield. The reaction of (-)-bornyl acetate with benzonitrile produced the racemic amide compound, (±)-exo-N-isobornylbenzamide, in 82% yield.

摘要

研究了在无溶剂条件下以碘为催化剂时酯与腈的反应。例如,乙酸1-苯乙酯在碘存在下与苯甲腈反应生成酰胺N-(1-苯乙基)苯甲酰胺。加水对促进酰胺化反应有效。研究并确定了最适宜的条件如下:温度=80℃,腈:醇:碘:水的摩尔比=1:3:0.2:1.0,反应时间=18小时。酰胺化反应活性取决于由酯形成的阳离子中间体的稳定性。只有乙酸2-苯基-2-丙酯与苯甲腈的反应没有生成酰胺化合物;相反,以90%的产率得到了环状化合物1,1,3-三甲基-3-苯基-2,3-二氢-1H-茚。乙酸(-)-冰片酯与苯甲腈反应生成外消旋酰胺化合物(±)-外型-N-异冰片基苯甲酰胺,产率为82%。

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