Kargar Hadi, Kia Reza, Tahir Muhammad Nawaz
Acta Crystallogr Sect E Struct Rep Online. 2012 Jul 1;68(Pt 7):o2120. doi: 10.1107/S1600536812025950. Epub 2012 Jun 16.
In t the title compound, C(14)H(12)BrN(3)O(2). H(2)O, the conformation of the C=N double bond in the hydrazide Schiff base mol-ecule is E. The dihedral angle between the benzene rings is 48.01 (11) °. An intra-molecular O-H⋯N hydrogen bond makes an S(6) ring motif. In the crystal, mol-ecules are linked through N-H⋯O (bifurcated acceptor) and O-H⋯O hydrogen bonds, forming two-dimensional networks lying parallel to (100).
在标题化合物C₁₄H₁₂BrN₃O₂·H₂O中,酰肼席夫碱分子中C=N双键的构象为E型。苯环之间的二面角为48.01 (11)°。分子内O—H⋯N氢键形成一个S(6)环模式。在晶体中,分子通过N—H⋯O(分叉受体)和O—H⋯O氢键相连,形成平行于(100)的二维网络。