Akhtar M, Alexander K, Boar R B, McGhie J F, Barton D H
Biochem J. 1978 Mar 1;169(3):449-63. doi: 10.1042/bj1690449b.
By using cell-free preparations of rat liver it was shown that the removal of the 14alpha-methyl group (C-32) of steroids containing either a delta7(8) or a delta8(9) double bond is attended exclusively by the formation of the corresponding 7,14- and 8,14-dienes respectively (structures of types III and VIII). Cumulative evidence from a variety of experimental approaches had led to the deduction that delta8(14)-steroids are not involved as intermediates on the major pathway of cholesterol biosynthesis. The metabolism of [32-3H]lanost-7-ene-3beta,32-diol (structure of type I) results in the formation of radioactive formic acid, no labelled formaldehyde being formed. By using appropriately labelled species of the compound (I) it was found that the release of formic acid and the formation of 4,4-dimethylcholesta-7,14-dien-3beta-ol (strurcture of type III) were closely linked processes, and that in the conversion of compound (I) into compound (III), 3-beta-hydroxylanost-7-en-32-al (II) is an obligatory intermediate. Both the conversion of lanost-7-ene-3beta,32-diol (I) into 3beta-hydroxylanost-7-en-32-al (II) and the further metabolism of the latter (II) to 4,4-dimethylcholesta-7,14-dien-3beta-ol (III) exhibited a requirement for NADPH and O2. This suggests that the oxidation of the 32-hydroxy group of compound (I) to the aldehyde group of compound (II) does not occur by the conventional alcohol dehydrogenase type of reaction, but may proceed by a novel mechanism involving the intermediacy of a gem-diol. A detailed overall pathway for the 14alpha-demethylation in cholesterol biosynthesis is considered, and proposals about the mechanism of individual steps in the pathway are made.
通过使用大鼠肝脏的无细胞制剂表明,含有δ7(8)或δ8(9)双键的类固醇的14α-甲基(C-32)的去除分别仅伴随着相应的7,14-二烯和8,14-二烯的形成(III型和VIII型结构)。来自各种实验方法的累积证据导致推断δ8(14)-类固醇不作为胆固醇生物合成主要途径的中间体参与。[32-3H]羊毛甾-7-烯-3β,32-二醇(I型结构)的代谢导致放射性甲酸的形成,未形成标记的甲醛。通过使用该化合物(I)的适当标记的种类发现,甲酸的释放和4,4-二甲基胆甾-7,14-二烯-3β-醇(III型结构)的形成是紧密相连的过程,并且在化合物(I)转化为化合物(III)的过程中,3-β-羟基羊毛甾-7-烯-32-醛(II)是必不可少的中间体。羊毛甾-7-烯-3β,32-二醇(I)转化为3β-羟基羊毛甾-7-烯-32-醛(II)以及后者(II)进一步代谢为4,4-二甲基胆甾-7,14-二烯-3β-醇(III)都表现出对NADPH和O2的需求。这表明化合物(I)的32-羟基氧化为化合物(II)的醛基不是通过传统的醇脱氢酶类型的反应发生的,而是可能通过涉及偕二醇中间体的新机制进行。考虑了胆固醇生物合成中14α-去甲基化的详细总体途径,并对该途径中各个步骤的机制提出了建议。