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四水合双[2-(2-硝基苯基)乙酸根-κO]钴(II)

Tetra-aqua-bis-[2-(2-nitro-phen-yl)acetato-κO]cobalt(II).

作者信息

Danish Muhammad, Tahir Muhammad Nawaz, Iftikhar Sana, Raza Muhammad Asam, Ashfaq Muhammad

机构信息

Department of Chemistry, Institute of Chemical and Biological Sciences, University of Gujrat, Gujrat 50700, Pakistan.

Department of Physics, University of Sargodha, Sargodha, Punjab, Pakistan.

出版信息

Acta Crystallogr E Crystallogr Commun. 2015 Feb 11;71(Pt 3):m59-60. doi: 10.1107/S2056989015002467. eCollection 2015 Mar 1.

DOI:10.1107/S2056989015002467
PMID:25844208
原文链接:https://pmc.ncbi.nlm.nih.gov/articles/PMC4350698/
Abstract

The mol-ecule of the title compound, [Co(C8H6NO4)2(H2O)4], is centrosymmetric. It is a cobalt(II) complex, bearing two (2-nitro-phen-yl)acetate and four aqua ligands. The coordination around the Co(II) atom is distorted octa-hedral, defined by four O atoms of water mol-ecules in the equatorial plane and by two carboxyl-ate O atoms at axial positions. The dihedral angles between the benzene ring and the acetate and nitro groups are 61.90 (10) and 19.21 (11)°, respectively. The water mol-ecules form O-H⋯O hydrogen bonds with the nitro and carboxyl-ate groups, leading to a layered structural arrangement parallel to (001).

摘要

标题化合物[Co(C₈H₆NO₄)₂(H₂O)₄]的分子具有中心对称性。它是一种钴(II)配合物，带有两个(2-硝基苯基)乙酸酯和四个水配体。Co(II)原子周围的配位环境为扭曲的八面体，赤道平面上由四个水分子的O原子定义，轴向位置由两个羧酸根O原子定义。苯环与乙酸酯和硝基之间的二面角分别为61.90 (10)°和19.21 (11)°。水分子与硝基和羧酸根基团形成O-H⋯O氢键，导致形成平行于(001)的层状结构排列。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/89e0/4350698/10f3d630a8d9/e-71-00m59-fig2.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/89e0/4350698/07ef75cfaa38/e-71-00m59-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/89e0/4350698/10f3d630a8d9/e-71-00m59-fig2.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/89e0/4350698/07ef75cfaa38/e-71-00m59-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/89e0/4350698/10f3d630a8d9/e-71-00m59-fig2.jpg

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