Maddison Wayne P
Department of Integrative Biology, University of California, Berkeley, CA, 94720.
Evolution. 1990 May;44(3):539-557. doi: 10.1111/j.1558-5646.1990.tb05937.x.
A method is presented for assessing whether changes in a binary character are more concentrated than expected by chance on certain branches of a phylogenetic tree. It can be used to test for correlated evolution of two characters by asking whether changes in the first character are significantly concentrated on those branches on which the second character has a specified state. Thus, one could test whether this specified state is associated with, and thus might enable or select, gains or losses in the first character. The probability of achieving a concentration as or more extreme than that observed under the null hypotheses that changes are distributed randomly on the cladogram is obtained by calculating (a) the number of ways that n gains and m losses can be distributed on the cladogram and (b) the number of ways that p gains q losses can be distributed on the branches of interest given n gains and m losses in the cladogram overall. Summing (b) for appropriate p and q then dividing by (a) yields the desired probability. Simulations suggest that biases resulting from errors in parsimony reconstructions of ancestral states are not extreme.
本文提出了一种方法,用于评估二元性状的变化是否比随机情况下更集中于系统发育树的某些分支上。它可用于通过询问第一个性状的变化是否显著集中于第二个性状具有特定状态的那些分支上,来检验两个性状的协同进化。因此,人们可以检验这种特定状态是否与第一个性状的获得或丧失相关联,从而可能促成或选择这些变化。在零假设(即变化在分支图上随机分布)下,获得与观察到的浓度相同或更极端浓度的概率,是通过计算(a)n次获得和m次丧失在分支图上的分布方式数量,以及(b)在分支图总体上有n次获得和m次丧失的情况下,p次获得和q次丧失在感兴趣分支上的分布方式数量来得到的。然后对合适的p和q求和(b),再除以(a),就得到了所需的概率。模拟表明,由祖先状态简约重建中的误差导致的偏差并不极端。