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含 NAD/NADH 功能化配体的 Rh(五甲基环戊二烯基)配合物的电化学行为。

Electrochemical behavior of a Rh(pentamethylcyclopentadienyl) complex bearing an NAD/NADH-functionalized ligand.

机构信息

Department of Chemistry, Graduate School of Science, Osaka City University, Sumiyoshi-ku, Osaka 558-8585, Japan.

出版信息

Dalton Trans. 2018 Apr 17;47(15):5207-5216. doi: 10.1039/c7dt04594h.

Abstract

A RhCp* (Cp* = pentamethylcyclopentadienyl) complex bearing an NAD+/NADH-functionalized ligand, [RhCp*(pbn)Cl]Cl ([1]Cl, pbn = (2-(2-pyridyl)benzo[b]-1,5-naphthyridine)), was synthesized. The cyclic voltammogram of [1]Cl in CH3CN shows two reversible redox waves at E1/2 = -0.58 and -1.53 V (vs. the saturated calomel electrode (SCE)), which correspond to the RhIII/RhI and pbn/pbn˙- redox couples, respectively. The addition of acetic acid to the solution afforded the proton-coupled two-electron reduction of [1]Cl at -0.62 V, from which [RhCp*(pbnHH)Cl]+ was selectively generated, probably via a hydride transfer from a RhIII-hydride intermediate to the pbn ligand. Complex [1]Cl is stable under acidic conditions, whereas a methyl proton of the Cp* moiety dissociates under basic conditions. The resulting anionic methylene group attacks the para carbon of the free pyridine of pbn, accompanied by protonation of the nitrogen atom of the ligand. As a result, treatment of [1]Cl with a base produces selectively the cyclic complex [1CH]Cl, which bears a reduced pbn framework (pbnCH). [1CH]Cl forms 1 : 1 adducts with PhCOO-via hydrogen bonding. A similar adduct, formed by a Ru-pbnHH scaffold and RCOO- (R = CH3, C6H5), has been reported to react with CO2 to produce HCOO- under concomitant regeneration of Ru-pbn. The adduct of [1CH]Cl with PhCOO-, however, lacks such hydride-donor ability, due to a steric barrier in the molecular structure of [1CH]Cl, which hampers the hydride transfer.

摘要

一种含有 NAD+/NADH 功能化配体的 RhCp*(Cp*=五甲基环戊二烯基)配合物,[RhCp*(pbn)Cl]Cl([1]Cl,pbn=(2-(2-吡啶基)苯并[b]-1,5-萘啶))被合成出来。[1]Cl 在 CH3CN 中的循环伏安图显示出两个在 E1/2=-0.58 和-1.53 V(相对于饱和甘汞电极(SCE))处可逆的氧化还原波,分别对应于 RhIII/RhI 和 pbn/pbn˙-氧化还原对。向溶液中加入乙酸,使得[1]Cl 在-0.62 V 处发生质子耦合的两电子还原,从而选择性地生成了[RhCp*(pbnHH)Cl]+,可能是通过 RhIII-氢化物中间体向 pbn 配体转移氢化物来实现的。配合物[1]Cl 在酸性条件下稳定,而 Cp* 部分的一个甲基质子在碱性条件下解离。所得的阴离子亚甲基基团攻击 pbn 中游离吡啶的对位碳,同时配体的氮原子质子化。结果,[1]Cl 与碱反应选择性地生成了环状配合物[1CH]Cl,其具有还原的 pbn 骨架(pbnCH)。[1CH]Cl 通过氢键与 PhCOO-形成 1:1 加合物。已经报道了具有 Ru-pbnHH 支架和 RCOO-(R=CH3,C6H5)的类似加合物,在 Ru-pbn 同时再生的情况下,与 CO2 反应生成 HCOO-。然而,[1CH]Cl 与 PhCOO-的加合物缺乏这种供氢能力,这是由于[1CH]Cl 分子结构中的空间位阻阻碍了氢化物转移。

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