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Ti 催化炔烃与烯烃和叠氮化物的碳氨化反应中,氧化还原中性机制相对于氧化还原机制的强烈偏好。

Strong Preference of the Redox-Neutral Mechanism over the Redox Mechanism for the Ti Catalysis Involved in the Carboamination of Alkyne with Alkene and Diazene.

机构信息

School of Chemical Sciences, University of the Chinese Academy of Sciences, Beijing, 100049, China.

出版信息

Chemistry. 2018 May 11;24(27):7010-7025. doi: 10.1002/chem.201800339. Epub 2018 Apr 30.

Abstract

Titanium catalysis generally prefers redox-neutral mechanisms. Yet it has been reported that titanium could promote bond formations in a way similar to reductive elimination. Accordingly, redox catalytic cycles involving Ti /Ti cycling have been considered. By studying, as an example, the carboamination of alkynes with alkenes and azobenzene catalyzed by the [Ti ]=NPh imido complex, we performed DFT computations to gain an understanding of how the "abnormal" catalysis takes place, thereby allowing us to clarify whether the catalysis really follows Ti /Ti redox mechanisms. The reaction first forms an azatitanacyclohexene by alkyne addition to the [Ti ]=NPh bond, followed by alkene insertion. The azatitanacyclohexene can either undergo C -C coupling, to afford bicyclo[3.1.0]imine, or β-H elimination, to yield a [Ti ]-H hydride, which then undergoes C =C or C =C insertion to give an α,β- or β,γ-unsaturated imine, respectively. Both the geometric and electronic structures indicate that the catalytic cycles proceed through redox-neutral mechanisms. The alternative redox mechanisms (e.g., by N-H or C-H reductive elimination) are substantially less favorable. We concluded that electronically, the Ti catalysis intrinsically favors the redox-neutral mechanism, because a redox pathway would involve Ti structures either in the triplet ground state or in the high-lying open-shell singlet state, but the involvement of triplet Ti structures is spin-forbidden and that of singlet Ti structures is energetically disadvantageous.

摘要

钛催化通常倾向于氧化还原中性机制。然而,据报道,钛可以以类似于还原消除的方式促进键的形成。因此,已经考虑了涉及 Ti/Ti 循环的氧化还原催化循环。通过研究炔烃与烯烃和偶氮苯的碳酰胺化反应为例,我们进行了 DFT 计算,以了解“异常”催化是如何发生的,从而使我们能够澄清该催化是否真的遵循 Ti/Ti 氧化还原机制。反应首先通过炔烃加成到[Ti]=NPh 键形成氮杂钛杂环己烯,然后进行烯烃插入。氮杂钛杂环己烯可以进行 C-C 偶联,生成双环[3.1.0]亚胺,或者进行β-H 消除,生成[Ti]-H 氢化物,然后进行 C=C 或 C=C 插入,分别得到α,β-或β,γ-不饱和亚胺。几何和电子结构都表明催化循环通过氧化还原中性机制进行。替代的氧化还原机制(例如,通过 N-H 或 C-H 还原消除)则明显不太有利。我们得出结论,从电子角度来看,Ti 催化本质上倾向于氧化还原中性机制,因为氧化还原途径将涉及三重态基态或高能单重态的 Ti 结构,但三重态 Ti 结构的参与是自旋禁阻的,而单重态 Ti 结构的参与在能量上是不利的。

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