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人类C反应蛋白的基因组DNA序列。

Genomic DNA sequence for human C-reactive protein.

作者信息

Lei K J, Liu T, Zon G, Soravia E, Liu T Y, Goldman N D

出版信息

J Biol Chem. 1985 Oct 25;260(24):13377-83.

PMID:2997165
Abstract

The gene for the prototype acute phase reactant, C-reactive protein, has been isolated from two lambda phage libraries containing inserted human DNA fragments using synthetic oligonucleotide probes. Nucleotide sequence analysis indicates that after coding for a signal peptide of 18 amino acids and the first two amino acids of the mature protein, there is an intron of 278 base pairs followed by the nucleotide sequence for the remaining 204 amino acids. The intron is unusual in that it contains on the positive strand a poly(A) stretch 16 nucleotides long and a poly(GT) region 30 nucleotides long which could adopt the Z-form of DNA. The nucleotide sequence reported here confirms the amino acid sequence of mature C-reactive protein as originally reported except that it codes for an additional 19 amino acids beginning at position 62. Thus DNA sequence analysis predicts that the mature protein consists of 206 amino acids rather than 187 as originally reported. The mRNA cap site is located 104 nucleotides from the start of the signal peptide and there is a 3' noncoding region 1.2 kilobase pairs in length. The gene has a typical promoter containing the sequences TATAAAT and CAAT 29 and 81 base pairs upstream, respectively, of the cap site.

摘要

利用合成寡核苷酸探针,已从两个含有插入人类DNA片段的λ噬菌体文库中分离出编码原型急性期反应物C反应蛋白的基因。核苷酸序列分析表明,在编码了18个氨基酸的信号肽和成熟蛋白的前两个氨基酸之后,有一个278个碱基对的内含子,接着是其余204个氨基酸的核苷酸序列。该内含子不同寻常之处在于,它在正链上含有一段16个核苷酸长的聚腺苷酸片段和一段30个核苷酸长的聚(GT)区域,后者可能呈现DNA的Z型构象。此处报道的核苷酸序列证实了最初报道的成熟C反应蛋白的氨基酸序列,只是它编码了从第62位开始的另外19个氨基酸。因此,DNA序列分析预测成熟蛋白由206个氨基酸组成,而非最初报道的187个。mRNA帽位点位于距信号肽起始位置104个核苷酸处,并且有一个长度为1.2千碱基对的3'非编码区。该基因有一个典型的启动子,分别在帽位点上游29和81个碱基对处含有序列TATAAAT和CAAT。

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