Department of Chemistry , Taiyuan Normal University , Jinzhong 030619 , China.
Humic Acid Engineering and Technology Research Center of Shanxi Province , Jinzhong 030619 , China.
J Phys Chem A. 2019 Nov 27;123(47):10263-10272. doi: 10.1021/acs.jpca.9b07043. Epub 2019 Nov 14.
The ruthenium(II)-catalyzed α-alkylation reaction of arylmethyl nitriles (phenylacetonitrile) using alcohols (ethanol) in toluene has been extensively investigated by means of SMD-M06-2X/6-311G(d,p)-LANL2dz (LAnL2dz for Ru, 6-311G(d,p) for other atoms) calculations. Detailed mechanistic schemes have been proposed and discussed. The catalytically active Ru(II) complex was generated by the base-induced KCl elimination from the catalyst precursor [(PNP)RuHCl(CO)]. The overall Ru(II) catalytic cycle consists of three basic processes: (1) ethanol-to-aldehyde transformation catalyzed by the 16-electron unsaturated ruthenium pincer catalyst; (2) a 16-electron unsaturated ruthenium pincer catalyst catalyzed condensation reaction of arylmethyl nitrile with aldehyde, which leads to PhC(CN)=CHCH; (3) hydrogenation of PhC(CN)=CHCH, which leads to the formation of the α-alkylated arylmethyl nitrile product (PhCH(CHCH)CN). The DFT results revealed that the rate-determining barrier of the overall reaction was 23.9 kcal/mol of the H-transfer step in the third process. The reaction of PhC(CN)=CHCH with the dihydride Ru complex, which is generated in the ethanol-to-aldehyde transformation process, is the more preferable hydrogenation mechanism than hydrogenation of vinyl nitrile-Ru complex by H. Using alcohol as the reactant not only fulfills the requirement of the borrowing-H strategy but also lowers the barriers of the H-migration steps.
钌(II)催化的芳基甲基腈(苯乙腈)与醇(乙醇)在甲苯中的α-烷基化反应已通过 SMD-M06-2X/6-311G(d,p)-LANL2dz(LAnL2dz 用于 Ru,6-311G(d,p) 用于其他原子)计算得到了广泛研究。提出并讨论了详细的机理方案。催化活性的 Ru(II)配合物是通过碱诱导从催化剂前体[(PNP)RuHCl(CO)]中消除 KCl 生成的。整体 Ru(II)催化循环由三个基本过程组成:(1)由 16 电子不饱和钌夹式催化剂催化的乙醇到醛的转化;(2)16 电子不饱和钌夹式催化剂催化的芳基甲基腈与醛的缩合反应,导致 PhC(CN)=CHCH;(3)PhC(CN)=CHCH 的加氢,导致α-烷基化芳基甲基腈产物(PhCH(CHCH)CN)的形成。DFT 结果表明,整个反应的速率决定步骤是第三步中 H 转移步骤的 23.9 kcal/mol。PhC(CN)=CHCH 与在乙醇到醛转化过程中生成的二氢化物 Ru 配合物的反应是比 H 氢化乙烯腈-Ru 配合物更有利的氢化机理。使用醇作为反应物不仅满足了借氢策略的要求,而且还降低了 H 迁移步骤的壁垒。