Nutrition and Food Technology Group, Food Engineering Department, Faculty of Pharmaceuticals and Food Sciences, University of Antioquia, Medellín, Colombia.
Nutrition and Food Technology Group, Food Engineering Department, Faculty of Pharmaceuticals and food sciences, University of Antioquia, Medellín, Colombia.
Curr Pharm Biotechnol. 2021;22(1):150-158. doi: 10.2174/1389201021666200807104636.
In modern society, there is a tendency to consume products with natural origins and minimum chemical additives. This has encouraged the replacement of synthetic antioxidants for the ones obtained from natural sources, such as the antioxidants acquired from enzymatic protein hydrolysates.
In this study, the process of enzymatic hydrolysis of proteins from bovine plasma, which produces hydrolysates with an Antioxidant Capacity (AC), was scaled up from 1 to 5 L.
An experimental design was developed in 1 L to evaluate the effect of the Substrate concentration (So) on the time needed to reach a Degree of Hydrolysis (DH) of 20% as well as the AC.
The best conditions in the 1 L reactor controlled by a Titrando 842 were transferred to 5L in a BioFlo310 reactor. These conditions were achieved at a ratio of 80g/L of the substrate and 0.89 AU of Alcalase 2.4L/g of the substrate in order to obtain a level of 16.36 ± 0.21min of the 20% of DH and antioxidant capacity of 58.98 ± 1.80%.
The results showed that DH depends significantly on So, while the antioxidant capacity only depends on the DH. Additionally, the dimensional analysis using Re as a scaling criterion allowed us to obtain the same results in the model (1 L) and the prototype (5 L).
在现代社会中，人们倾向于消费具有天然来源和最小化学添加剂的产品。这鼓励了用天然来源获得的抗氧化剂替代合成抗氧化剂，例如从酶蛋白水解物中获得的抗氧化剂。
在本研究中，将从牛血浆中蛋白质的酶解过程从 1L 放大到 5L，以获得具有抗氧化能力（AC）的水解产物。
在 1L 中设计了一个实验，以评估底物浓度（So）对达到 20%水解度（DH）所需时间以及 AC 的影响。
在 Titrando 842 控制的 1L 反应器中最佳条件被转移到 5L 的 BioFlo310 反应器中。这些条件是在底物比为 80g/L 和底物的 Alcalase 2.4L/g 为 0.89 AU 的情况下实现的，以达到 20%DH 和抗氧化能力为 58.98±1.80%的水平。
结果表明，DH 显著依赖于 So，而抗氧化能力仅依赖于 DH。此外，使用 Re 作为缩放标准的量纲分析使我们能够在模型（1L）和原型（5L）中获得相同的结果。
