Miloserdov Fedor M, Isaac Connie J, Beck Madeleine L, Burnage Arron L, Farmer James C B, Macgregor Stuart A, Mahon Mary F, Whittlesey Michael K
Department of Chemistry, University of Bath, Bath BA2 3QD, United Kingdom.
Institute of Chemical Sciences, School of Engineering and Physical Sciences, Heriot-Watt University, Edinburgh EH14 4AS, United Kingdom.
Inorg Chem. 2020 Nov 2;59(21):15606-15619. doi: 10.1021/acs.inorgchem.0c01683. Epub 2020 Oct 19.
The preparation and reactivity with H of two Ru complexes of the novel ZnPhos ligand (ZnPhos = Zn(-CHPPh)) are described. Ru(ZnPhos)(CO) () and Ru(ZnPhos)(IMe) (; IMe = 1,3,4,5-tetramethylimidazol-2-ylidene) are formed directly from the reaction of Ru(PPh)(CHPPh)(ZnMe) () or Ru(PPh)HCl/LiCHTMS/ZnMe with CO and IMe, respectively. Structural and electronic structure analyses characterize both and as Ru(0) species in which Ru donates to the Z-type Zn center of the ZnPhos ligand; in , Ru adopts an octahedral coordination, while displays square-pyramidal coordination with Zn in the axial position. Under photolytic conditions, loses CO to give Ru(ZnPhos)(CO) that then adds H over the Ru-Zn bond to form Ru(ZnPhos)(CO)(μ-H) (). In contrast, reacts directly with H to set up an equilibrium with Ru(ZnPhos)(IMe)H (), the product of oxidative addition at the Ru center. DFT calculations rationalize these different outcomes in terms of the energies of the square-pyramidal Ru(ZnPhos)L intermediates in which Zn sits in a basal site: for L = CO, this is readily accessed and allows H to add across the Ru-Zn bond, but for L = IMe, this species is kinetically inaccessible and reaction can only occur at the Ru center. This difference is related to the strong π-acceptor ability of CO compared to IMe. Steric effects associated with the larger IMe ligands are not significant. Species can be considered as a Ru(0)L species that is stabilized by the Ru→Zn interaction. As such, it is a rare example of a stable Ru(0)L species devoid of strong π-acceptor ligands.
描述了新型ZnPhos配体(ZnPhos = Zn(-CHPPh))的两种Ru配合物的制备及其与H的反应活性。Ru(ZnPhos)(CO) () 和Ru(ZnPhos)(IMe) (; IMe = 1,3,4,5 - 四甲基咪唑 - 2 - 亚基) 分别由Ru(PPh)(CHPPh)(ZnMe) () 或Ru(PPh)HCl/LiCHTMS/ZnMe与CO和IMe直接反应形成。结构和电子结构分析表明 和 均为Ru(0) 物种,其中Ru向ZnPhos配体的Z型Zn中心供电子;在 中,Ru采用八面体配位,而 在轴向位置与Zn呈现四方锥配位。在光解条件下, 失去CO生成Ru(ZnPhos)(CO),然后H通过Ru - Zn键加成形成Ru(ZnPhos)(CO)(μ - H) ()。相比之下, 直接与H反应建立与Ru(ZnPhos)(IMe)H () 的平衡,Ru(ZnPhos)(IMe)H () 是Ru中心氧化加成的产物。密度泛函理论计算根据四方锥Ru(ZnPhos)L中间体(其中Zn位于基面位置)的能量解释了这些不同的结果:对于L = CO,这种中间体很容易形成,并且允许H通过Ru - Zn键加成,但对于L = IMe,这种物种在动力学上无法形成,反应只能在Ru中心发生。这种差异与CO相对于IMe较强的π - 受体能力有关。与较大的IMe配体相关的空间效应并不显著。物种 可被视为通过Ru→Zn相互作用稳定的Ru(0)L物种。因此,它是一个罕见的不含强π - 受体配体的稳定Ru(0)L物种的例子。