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荚膜多糖与人类肠道微生物的免疫反应相关。

Capsular polysaccharide correlates with immune response to the human gut microbe .

机构信息

Department of Biological Chemistry & Molecular Pharmacology, Harvard Medical School, Boston, MA 02115.

Department of Molecular Biology, Massachusetts General Hospital, Boston, MA 02114.

出版信息

Proc Natl Acad Sci U S A. 2021 May 18;118(20). doi: 10.1073/pnas.2007595118.

Abstract

Active inflammatory bowel disease (IBD) often coincides with increases of , a gut microbe found in nearly everyone. It was not known how, or if, this correlation contributed to disease. We investigated clinical isolates of to identify molecular mechanisms that would link to inflammation. Here, we show that only some isolates of produce a capsular polysaccharide that promotes a tolerogenic immune response, whereas isolates lacking functional capsule biosynthetic genes elicit robust proinflammatory responses in vitro. Germ-free mice colonized with an isolate of lacking a capsule show increased measures of gut inflammation compared to those colonized with an encapsulated isolate in vivo. These observations in the context of our earlier identification of an inflammatory cell-wall polysaccharide reveal how some strains of could drive the inflammatory responses that characterize IBD.

摘要

活动性炎症性肠病 (IBD) 常伴有肠道微生物 的增加,这种微生物几乎存在于每个人体内。其是否会导致疾病以及如何导致疾病尚不清楚。我们研究了 的临床分离株,以确定将 与炎症联系起来的分子机制。在这里,我们表明只有一些 的分离株产生一种荚膜多糖,可促进耐受免疫反应,而缺乏功能性荚膜生物合成基因的分离株在体外会引起强烈的促炎反应。与用缺乏荚膜的 分离株定植的无菌小鼠相比,用带有荚膜的 分离株定植的无菌小鼠体内的肠道炎症标志物增加。这些观察结果结合我们之前对炎症细胞壁多糖的鉴定,揭示了某些 菌株如何引发 IBD 特征的炎症反应。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/d193/8157926/29e1b82767b4/pnas.2007595118fig01.jpg

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