Mishra Saikat, Kumar Shibaditya, Bhandari Anirban, Das Aniruddha, Mondal Pallav, Hundal Geeta, Olmstead Marilyn M, Patra Apurba K
Department of Chemistry, National Institute of Technology Durgapur, Mahatma Gandhi Avenue, Durgapur 713209, West Bengal, India.
Department of Chemistry, Guru Nanak Dev University, Amritsar 143005, Punjab, India.
Inorg Chem. 2022 May 2;61(17):6421-6437. doi: 10.1021/acs.inorgchem.1c04038. Epub 2022 Apr 22.
Four Schiff base ligands of the general formulas [6-()-2-pyridyl--(2'-methylthiophenyl)methylenimine] (L1) and 6--chlorophenyl-2-pyridyl--(2'-phenylthiophenyl)methylenimine (L2), where R = H, Me, -ClPh, and their bis-ligand copper(II) and copper(I) complexes, - and -, respectively, were synthesized and characterized. The reactivities of - with nitric oxide (NO) gas and of - with solid NOBF (NO) were examined in dry acetonitrile in the presence and absence of water (HO). The results revealed that, , complexes - (or -) reacts with NO (or NOBF), leading to imine C═N bond cleavage of both (or one) Schiff base(s) that generates 2 (or 1) equiv of 2-(methyl/phenyl)thiobenzenediazonium perchlorates (/) and the corresponding picolaldehyde (Pial) via a copper nitrosyl of a {CuNO}-type intermediate. , the in situ formed Pial get oxidized to the corresponding picolinic acid (PicH) via an in situ formed LCuOH intermediate (LCu + HO-NO → LCuOH + NO; L = L1/L2/Pic and ν of CuOH = 3650 cm) and subsequently produces, with the aid of NO oxidant, the picolinate-ligated copper(II) complexes (i) [(Pic)Cu] (), [(Pic)Cu(NO)]·HO (·HO), or [(Pic)Cu] () when NO reacts with - or (ii) [(Pic)Cu(L1/L2)] when NO reacts with -. The Cu to Cu reduction of [(Pic)Cu(L1/L2)] is essential for C═N cleavage of the remaining L1/L2 Schiff base; excess NO can do it. The X-ray structures (, , , , , and ) and spectroscopic results revealed the role of Cu, NO, NO, and HO, shedding light on the mechanism of C═N bond cleavage and the oxidation of pyridine-2-aldehyde to pyridine-2-carboxylic acid. The reaction of with NO revealed that the terminal N of the N group of originates from NO [ν = 2248 cm and ν = 2212 cm].
合成并表征了通式为6 - ( ) - 2 - 吡啶基 - (2'-甲基硫苯基)亚甲基亚胺和6 - 氯苯基 - 2 - 吡啶基 - (2'-苯基硫苯基)亚甲基亚胺(L2)的四种席夫碱配体,其中R = H、Me、 - ClPh,以及它们的双配体铜(II)和铜(I)配合物,分别为 - 和 - 。在有无水(H₂O)存在的情况下,于干燥乙腈中考察了 - 与一氧化氮(NO)气体以及 - 与固体NOBF₄(NO⁺)的反应活性。结果表明,配合物 - (或 - )与NO(或NOBF₄)反应,导致一个(或两个)席夫碱的亚胺C═N键断裂,通过{CuNO}型中间体的亚硝酰铜生成2(或1)当量的2 - (甲基/苯基)硫代苯重氮高氯酸盐( / )和相应的吡啶 - 2 - 甲醛(Pial)。此外,原位形成的Pial通过原位形成的LCuOH中间体(LCu + H₂O - NO → LCuOH + NO;L = L1/L2/Pic且CuOH的ν = 3650 cm⁻¹)被氧化为相应的吡啶 - 2 - 羧酸(PicH),随后在NO氧化剂的作用下,当NO与 - 反应时生成吡啶甲酸配位的铜(II)配合物(i)(Pic)₂Cu )、[(Pic)₂Cu(NO)]·H₂O(·H₂O)或(Pic)₂Cu,或者当NO与 - 反应时生成[(Pic)₂Cu(L1/L2)]。[(Pic)₂Cu(L1/L2)]从Cu(II)到Cu(I)的还原对于剩余L1/L2席夫碱的C═N断裂至关重要;过量的NO也能做到这一点。X射线结构( 、 、 、 、 和 )以及光谱结果揭示了Cu、NO、NO⁺和H₂O 的作用,阐明了C═N键断裂以及吡啶 - 2 - 醛氧化为吡啶 - 2 - 羧酸的机理。 与NO的反应表明, 的N基团的末端N源自NO[ν = 2248 cm⁻¹和ν = 2212 cm⁻¹]。