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C57BL/10(B10)小鼠的一种新的红细胞抗原。

A new erythrocytic antigen of C57BL/10 (B10) mice.

作者信息

Walker M C, Phillips-Quagliata J M

出版信息

Proc Soc Exp Biol Med. 1985 Mar;178(3):402-6. doi: 10.3181/00379727-178-42023.

Abstract

A new antigen, detectable on murine erythrocytes by hemagglutination assay with a (BALB/cCrl X SWR/J)F1 anti-B10.D2n/Sn alloantiserum, is described. Among the inbred and congenic mouse strains tested for reactivity with the antiserum, only the immunizing strain, B10.D2, and its congenic resistant partner, C57BL/10 (B10), reacted. Three other C57 strains, C57BL/6J, C57BL/6By, and C57L, were negative for the antigen. F1 hybrids between B10 and BALB/c, an antigen-negative strain, were positive for the antigen indicating that its expression is dominant. Typing of 39 (BALB/c X (BALB/c X B10)F1) and 62 [BALB/c X B10)F1 X BALB/c) backcross mice revealed that a single gene controls expression of the antigen. The gene is autosomal and not linked to H-2, Ly-4, or the c (albino) or b coat color genes.

摘要

描述了一种新抗原,该抗原可通过用(BALB/cCrl×SWR/J)F1抗B10.D2n/Sn同种异体抗血清进行血凝试验在小鼠红细胞上检测到。在测试与该抗血清反应性的近交系和同源近交系小鼠品系中,只有免疫品系B10.D2及其同源抗性品系C57BL/10(B10)有反应。其他三个C57品系,C57BL/6J、C57BL/6By和C57L,该抗原呈阴性。B10与抗原阴性品系BALB/c之间的F1杂种该抗原呈阳性,表明其表达是显性的。对39只(BALB/c×(BALB/c×B10)F1)和62只[BALB/c×B10)F1×BALB/c]回交小鼠的分型显示,一个基因控制该抗原的表达。该基因是常染色体基因,与H-2、Ly-4或c(白化)或b毛色基因不连锁。

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