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2-羟基-5-硝基苄基溴与α-乳白蛋白的组氨酸-32反应的化学过程

The chemistry of the reaction of 2-hydroxy-5-nitrobenzyl bromide with his-32 of alpha-lactalbumin.

作者信息

Barman T E

出版信息

Eur J Biochem. 1978 Feb;83(2):465-71. doi: 10.1111/j.1432-1033.1978.tb12112.x.

DOI:10.1111/j.1432-1033.1978.tb12112.x
PMID:415861
Abstract

His-32 of bovine or human alpha-lactalbumin reacts with the tryptophan reagent 2-hydroxy-5-nitrobenzyl bromide at pH 7. The reaction depends on the native conformation of the alpha-lactalbumin molecule and it is restricted to position 1 of the imidazole nucleus. The synthesis and characterization of 1-(2-hydroxy-5-nitrobenzyl)-histidine, 3-(2-hydroxy-5-nitrobenzyl)-histidine and 1,3-bis(2-hydroxy-5-nitrobenzyl)-histidine are described.

摘要

牛或人α-乳白蛋白的His-32在pH 7下与色氨酸试剂2-羟基-5-硝基苄基溴反应。该反应取决于α-乳白蛋白分子的天然构象，且仅限于咪唑核的1位。本文描述了1-(2-羟基-5-硝基苄基)-组氨酸、3-(2-羟基-5-硝基苄基)-组氨酸和1,3-双(2-羟基-5-硝基苄基)-组氨酸的合成与表征。

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[Chemical modification of tryptophan residues of leucyl tRNA synthetase by N-bromosuccinimide and 2-hydroxy-5-nitrobenzyl bromide].[用N-溴代琥珀酰亚胺和2-羟基-5-硝基苄基溴对亮氨酰tRNA合成酶色氨酸残基进行化学修饰]
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