Schwarz L R, Summer K H, Schwenk M
Eur J Biochem. 1979 Mar;94(2):617-22. doi: 10.1111/j.1432-1033.1979.tb12932.x.
Kinetics of transport and metabolism of bromosulfophthalein have been studied in isolated liver cells in a dose-dependent manner obtaining the following results. The disposition of bromosulfophthalein in suspensions of isolated liver cells is similar to the turnover in the whole liver. The initial maximal rate of uptake of bromosulfophthalein is 2--3 times faster than intracellular conjugation with glutathione. Conjugation proceeds to an equilibrium between intracellular substrate (bromosulfophthalein) and product (bromosulfophthalein-glutathione conjugate) which are both transiently accumulated in the cell. Formation of bromosulfophthalein-glutathione is accompanied by an equimolar decrease of glutathione. The bromosulfophthalein-glutathione conjugate is slowly released from the cells in an energy-dependent and saturable transport process. The maximal velocity of excretion amounts to only 6% of the maximal velocity of uptake and to 20% of the maximal velocity of conjugation. Excretion, therefore, represents the slowest step in the overall turnover.
已在分离的肝细胞中以剂量依赖方式研究了溴磺酞的转运和代谢动力学,得到以下结果。溴磺酞在分离的肝细胞悬液中的处置情况与在整个肝脏中的周转情况相似。溴磺酞的初始最大摄取速率比其与谷胱甘肽的细胞内结合快2至3倍。结合过程会达到细胞内底物(溴磺酞)和产物(溴磺酞 - 谷胱甘肽共轭物)之间的平衡,二者都会在细胞中短暂积累。溴磺酞 - 谷胱甘肽的形成伴随着谷胱甘肽等摩尔量的减少。溴磺酞 - 谷胱甘肽共轭物通过一个能量依赖且可饱和的转运过程从细胞中缓慢释放。排泄的最大速度仅为摄取最大速度的6%,为结合最大速度的20%。因此,排泄是整个周转过程中最慢的步骤。