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酿酒酵母冷休克细胞、原生质体和阻遏细胞对生物素的摄取:缺乏反馈控制。

Biotin uptake by cold-shocked cells, spheroplasts, and repressed cells of Saccharomyces cerevisiae: lack of feedback control.

作者信息

Cicmanec J F, Lichstein H C

出版信息

J Bacteriol. 1974 Sep;119(3):718-25. doi: 10.1128/jb.119.3.718-725.1974.

Abstract

Cold-osmotic-shocked cells and spheroplasts of Saccharomyces cerevisiae (ATCC 9896) display a biotin uptake system similar to that observed in intact cells. 2-Mercaptoethanol was found to inhibit biotin transport. Cells repressed for biotin uptake by growth in excess biotin (25 ng/ml) possess an energy-dependent transport system that has a K(m) for biotin of 6.6 x 10(-7) M and a V(max) equal to 39 pmol per mg (dry weight) per min. A similar K(m) (6.4 x 10(-7) M) but a considerably higher V(max) (530 pmol per mg (dry weight) per min) was determined for biotin uptake by cells grown in sufficient biotin (0.25 ng/ml). The V(max) rates of biotin uptake by both repressed and derepressed cells were increased approximately 35-fold in the presence of glucose. These yeast cells appear to regulate their biotin uptake by two mechanisms. An exit system provides for immediate adjustments, whereas turnover of the transport system and repression of new synthesis establishes a slower adaptation to changes in the environment. Feedback inhibition was ruled out as a mechanism of regulation of transport.

摘要

酿酒酵母(ATCC 9896)的冷渗透休克细胞和原生质体表现出一种与完整细胞中观察到的类似的生物素摄取系统。发现2-巯基乙醇可抑制生物素转运。通过在过量生物素(25 ng/ml)中生长而被抑制生物素摄取的细胞具有一种能量依赖性转运系统,该系统对生物素的K(m)为6.6×10(-7) M,V(max)等于每分钟每毫克(干重)39 pmol。对于在充足生物素(0.25 ng/ml)中生长的细胞摄取生物素,测定了类似的K(m)(6.4×10(-7) M),但V(max)相当高(每分钟每毫克(干重)530 pmol)。在葡萄糖存在下,受抑制和去抑制细胞摄取生物素的V(max)速率均增加约35倍。这些酵母细胞似乎通过两种机制调节其生物素摄取。一种排出系统可进行即时调节,而转运系统的周转和新合成的抑制则建立起对环境变化较慢的适应性。排除了反馈抑制作为转运调节机制的可能性。

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