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一种新的含有腺嘌呤磷酸核糖转移酶人类基因的简化型人-小鼠体细胞杂种。

A new reduced human-mouse somatic cell hybrid containing the human gene for adenine phosphoribosyltransferase.

作者信息

Kusano T, Long C, Green H

出版信息

Proc Natl Acad Sci U S A. 1971 Jan;68(1):82-6. doi: 10.1073/pnas.68.1.82.

Abstract

A system that selects for the gene directing synthesis of the enzyme adenine phosphoribosyltransferase (APRT) uses the antibiotic alanosine to prevent endogenous synthesis of adenylic acid. With the aid of this system, a new series of human-mouse hybrids has been prepared between wild type human diploid fibroblasts and an enzyme-deficient mouse line. Survival of the hybrids depended upon the presence of the APRT, which was shown to have the isoelectric pH characteristic of the human enzyme and not that of the mouse. Reduced hybrids containing the enzyme lacked all human biarmed chromosomes, so that unless a rearrangement had occurred, the aprt gene must be located on an acrocentric chromosome. The hybrid cells became APRT(-) with a frequency of 2 x 10(-3), probably by loss of the human aprt chromosome. The APRT(-) progeny could be obtained selectively by growth in medium containing fluoroadenine.

摘要

一种用于选择指导腺嘌呤磷酸核糖转移酶(APRT)合成的基因的系统,使用丙氨酸阻止腺苷酸的内源性合成。借助该系统,已在野生型人二倍体成纤维细胞与一种酶缺陷型小鼠品系之间制备了一系列新的人-鼠杂种。杂种的存活取决于APRT的存在,已证明其具有人酶的等电pH特性,而非小鼠酶的等电pH特性。含有该酶的减数杂种缺乏所有人类双臂染色体,因此除非发生重排,aprt基因必定位于一条近端着丝粒染色体上。杂种细胞以2×10⁻³的频率变为APRT(-),可能是由于丢失了人aprt染色体。通过在含有氟腺嘌呤的培养基中生长,可以选择性地获得APRT(-)后代。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/5f6f/391107/c21eb88a9cab/pnas00076-0091-a.jpg

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