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两种底物对单一酶的竞争。以羟基类固醇脱氢酶反应为例的一个简单动力学定理。

Competition of two substrates for a single enzyme. A simple kinetic theorem exemplified by a hydroxy steroid dehydrogenase reaction.

作者信息

Pocklington T, Jeffery J

出版信息

Biochem J. 1969 Apr;112(3):331-4. doi: 10.1042/bj1120331.

Abstract
  1. If two compounds are substrates for a single enzyme, and do not form any ternary complex with the enzyme or combine directly with each other, then the total initial rate of reaction for a mixture of the two compounds may be greater than the rate for either compound alone, or may lie between the rates for the compounds alone. It is the concentration of the compound with the higher maximum velocity that determines which applies, and there is one concentration of the compound of higher maximum velocity at which the total rate of reaction is independent of the presence or absence of the substrate of lower maximum velocity. The values concerned are derived. 2. An example is given of 5alpha-androstan-3-one and 5alpha-androstane-3,16-dione as substrates competing for a hydroxy steroid-NAD oxidoreductase (EC 1.1.1.53).
摘要
  1. 如果两种化合物是单一酶的底物,并且不与该酶形成任何三元复合物,也不直接相互结合,那么这两种化合物混合物的总初始反应速率可能大于单独一种化合物的反应速率,或者介于单独两种化合物的反应速率之间。是具有较高最大反应速度的化合物的浓度决定了适用哪种情况,并且存在一个具有较高最大反应速度的化合物浓度,此时总反应速率与具有较低最大反应速度的底物的存在与否无关。相关数值是推导得出的。2. 给出了一个例子,5α-雄甾烷-3-酮和5α-雄甾烷-3,16-二酮作为底物竞争羟基类固醇-NAD氧化还原酶(EC 1.1.1.53)。

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