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钠、钾和氯离子对兔窦房结细胞静息膜电位的影响。

The effect of Na, K and Cl ions on the resting membrane potential of sino-atrial node cell of the rabbit.

作者信息

Seyama I

出版信息

Jpn J Physiol. 1977;27(5):577-88. doi: 10.2170/jjphysiol.27.577.

Abstract

The resting membrane potential of S-A node cell was investigated by observing the response of the membrane potential to change in [K+]O or [Cl-]O under the presence or absence of Na ion. The slope of the change in membrane potential per decade change in [K+]O increased from 12.3 to 44 mV by removal of Na ion from the external medium, suggesting an extensive contribution of Na ion to the resting membrane potential. To determine the relative conductance between Na and K ions, Cl ion in Tyrode solution was substituted with SCN ion, which is 2.1 times more permeable than Cl ion, in order to eliminate the contribution of Cl concentration cell to the resting membrane potential. The contribution of the Cl ion to the resting membrane potential could be examined only in Na-free medium. Acetate ion has been reported to be 0.5 times less permeable than Cl ion. The replacement of Cl ion by acetate ion in various proportions caused a transient depolarization. The slope of this transient depolarization per decade change of [Cl-]O between 10 to 100 mM was determined to be -6.8mV. Under the assumption that the resting membrane potential could be determined by the parallel concnetration cells for Na, K and Cl, relative conductance ratio between K, Na and Cl was calculated to be 1:0.58:0.15.

摘要

通过观察在有无钠离子存在的情况下膜电位对细胞外液中[K⁺]O或[Cl⁻]O变化的反应,研究了窦房结细胞的静息膜电位。通过从细胞外液中去除钠离子,每十倍[K⁺]O变化时膜电位变化的斜率从12.3 mV增加到44 mV,这表明钠离子对静息膜电位有很大贡献。为了确定钠离子和钾离子之间的相对电导率,用硫氰酸根离子替代台氏液中的氯离子(硫氰酸根离子的通透性比氯离子高2.1倍),以消除氯离子浓度差电池对静息膜电位的影响。氯离子对静息膜电位的贡献只能在无钠培养基中进行检测。据报道,醋酸根离子的通透性比氯离子低0.5倍。用不同比例的醋酸根离子替代氯离子会引起短暂的去极化。在10至100 mM之间,每十倍[Cl⁻]O变化时这种短暂去极化的斜率被确定为-6.8 mV。假设静息膜电位可由钠离子、钾离子和氯离子的并联浓度差电池决定,计算出钾离子、钠离子和氯离子之间的相对电导率比为1:0.58:0.15。

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